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There are seven possible digits for the first digit and 6 digits for the second (minus one digit for the digit used as the first digit) and 5 options for the last digit (minus one again for the second digit) and then you just multiply them all together to get a total possible combination of 210 numbers that are possible.

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A polynomial of degree zero is a constant term

The grouping method of factoring can still be used when only some of the terms share a common factor A True B False

The sum or difference of p and q is the of the x-term in the trinomial

A number a power of a variable or a product of the two is a monomial while a polynomial is the of monomials

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Q: How many different three digit numbers can you form using the digits 1 2 3 5 6 7 and 9 without repetition?
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How many different two digit numbers can you form using the digits 1 2 5 7 8 and 9 with repetition?

30 without repetition (6P2) 66 with repetition (12C2)


How many numbers can be formed using the digits 37 and 9 without repetition?

15 of them.


How many three digit numbers can be formed using the digits 873 and 6 without repetition?

I take it that you want to make three digits numbers with 8,7,3, and 6 without repetition. The first digit cane be selected from among 4 digits, the second from 3 digits, the third digit from 2, hence the number of three digit numbers that can be formed without repetition is 4 x 3 x 2 = 24


How many four digits numbers can be made with 1 4 5 9 without repetition?

24


How many 3-digit numbers can be formed by the digits 4 5 9 without repetition?

Six (6)


Where d represents a digit from 0 9 how many different ISBN numbers are possible if repetition of digits is allowed?

There are 10 to the 10th power possibilities of ISBN numbers if d represents a digit from 0 to 9 and repetition of digits are allowed. That means there are 10,000,000,000 ISBN numbers possible.


How many different numbers can you form using all four numbers of 1 9 8 4?

The four digits can be used to produce infinitely many different numbers if repetition is permitted. Without repetition, there are 24 possible numbers. A lot more can be produced if the numbers are combined using binary oprations, fore example, 19 * 8/4 = 19*2 = 38.


How many two digit numbers can you form using the digits 1235679 with repetition allowed?

You have seven different digits (symbols) to choose from, so you can form seven different one digit numbers and 7×7=72=49 different two digit numbers.


How many 3 digit numbers can be formed using the digits 1 to 9 without repetition?

9*8*7 = 504 of them.


How many 3 digit numbers can be formed by the digits 4 5 9 without repetition?

3*2*1 = 6 of them.


How many 3 digit numbers are possible from the digits 012345?

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How many 13 digit numbers are possible by using the digits 12345 which are divisible by 4 if repetition of digits is not allowed?

If repetition of digits isn't allowed, then no13-digit sequencescan be formed from only 5 digits.