13 whole ones, and 1/3rd of another one.
3
3
40/15 = 8/3
40 with 3 remaining 283 - 3 = 280 = 7 x 40
3 with 17 remaining 137 - 17 = 120 = 40 x 3
The answer is 13 with remainder 1, or 13⅓ = 13.3 recurring.
13 R 1
To determine how many times 40 can go into 136, you would perform a division operation. When you divide 136 by 40, the result is 3 with a remainder of 16. This means that 40 can go into 136 three times, with 16 remaining.
4 times with a remainder of 3
Exactly 40 times
3 times with a remaider of 29
40 ÷ 6 = 6 r 4 or 6 2/3