3
40/15 = 8/3
3 with 17 remaining 137 - 17 = 120 = 40 x 3
40 with 3 remaining 283 - 3 = 280 = 7 x 40
3 times - with 3 remainder<br><br>3 x 40 = 120<br>
exactly 40 times
The answer is 13 with remainder 1, or 13⅓ = 13.3 recurring.
85 can go into 255 3 times.
3 with remainder 7.
13 with remainder 1.
13 R 1
40 times