3
40/15 = 8/3
40 times.
3 with 17 remaining 137 - 17 = 120 = 40 x 3
40 with 3 remaining 283 - 3 = 280 = 7 x 40
The answer is 13 with remainder 1, or 13⅓ = 13.3 recurring.
85 can go into 255 3 times.
13 R 1
2 times with 30 left over if you need an exact number is 2 and 30/40 (or 3/4) 110 / 40 = 2.75 or 2 3/4
3 times with a remaider of 29
4 times with a remainder of 3
40 ÷ 6 = 6 r 4 or 6 2/3