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840 As with any puzzle of this type, you need to work out how many ways there are of choosing the first digit. The you multiply that by the number of ways of choosing the second digit, then you multiply that by the number of ways of choosing the third digit, etc So, there are seven different digits available to be chosen for the first digit. Then there are six left to be chosen for the second.... and so on. This gives us 7 x 6 x 5 x 4 which equals 840.

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Q: How many 4-digit numbers can be formed by the digits 1 2 3 4 5 6 7 using each digit exactly once?
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