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Numbers formed should be of at least 3 digits means they may be of 3 digits, 4 digits, 5 digits or 6 digits.

There are 6 choices for digit in the units place. There are 5 and 4 choices for digits in ten and hundred’s place respectively.

So, total number of ways by which 3 digits numbers can be formed = 6.5.4 = 120

Similarly, the total no.of ways by which 4 digits numbers can be formed = 6.5.4.3 = 360.

the total no. of ways by which 5 digits numbers can be formed = 6.5.4.3.2 = 720.

The total no.of ways by which 4 digits numbers can be formed = 6.5.4.3.2.1 = 720.

So, total no.of ways by which the numbers of at least 3 digits can be formed = 120 + 360 + 720 + 720 = 1920.

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Infinitely many. For example, 123, 1231, 12321, 1212123, are all made from three (not tree!) different digits.

Q: How many numbers of at least tree different digits can be formed from the integers 123456?

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279,999,720

either irrational numbers, integers, integers, rational numbers, or whole numbers

100000 of course. If digits have to be different then 123456.

Only one. 123456.

192 ways

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279,999,720

12 numbers.

either irrational numbers, integers, integers, rational numbers, or whole numbers

6*6*3 = 108 numbers.

6*5*4*3*2*1=720 possible numbers

Only one. 123456.

100000 of course. If digits have to be different then 123456.

None. Extremely simple proof: To be divisible by 5 the units digit must be 5. But then it would not be divisible by 2.

192 ways

The number of six digit numbers that you can make from ten different digits ifrepetitions of same digit on the six digit number is allowed is 1 000 000 numbers(including number 000 000).If no repetitions of the the same digit are allowed then you have:10P6 = 10!/(10-6)! = 151 200 different six digit numbers(six digit permutations form 10 different digits).

Two integers.

There is only one number and that is 123456.