Numbers formed should be of at least 3 digits means they may be of 3 digits, 4 digits, 5 digits or 6 digits.
There are 6 choices for digit in the units place. There are 5 and 4 choices for digits in ten and hundred’s place respectively.
So, total number of ways by which 3 digits numbers can be formed = 6.5.4 = 120
Similarly, the total no.of ways by which 4 digits numbers can be formed = 6.5.4.3 = 360.
the total no. of ways by which 5 digits numbers can be formed = 6.5.4.3.2 = 720.
The total no.of ways by which 4 digits numbers can be formed = 6.5.4.3.2.1 = 720.
So, total no.of ways by which the numbers of at least 3 digits can be formed = 120 + 360 + 720 + 720 = 1920.
279,999,720
either irrational numbers, integers, integers, rational numbers, or whole numbers
Only one. 123456.
100000 of course. If digits have to be different then 123456.
None. Extremely simple proof: To be divisible by 5 the units digit must be 5. But then it would not be divisible by 2.
279,999,720
6*6*3 = 108 numbers.
6*5*4*3*2*1=720 possible numbers
either irrational numbers, integers, integers, rational numbers, or whole numbers
Only one. 123456.
100000 of course. If digits have to be different then 123456.
None. Extremely simple proof: To be divisible by 5 the units digit must be 5. But then it would not be divisible by 2.
192 ways
The number of six digit numbers that you can make from ten different digits ifrepetitions of same digit on the six digit number is allowed is 1 000 000 numbers(including number 000 000).If no repetitions of the the same digit are allowed then you have:10P6 = 10!/(10-6)! = 151 200 different six digit numbers(six digit permutations form 10 different digits).
Two integers.
99876543210
You get the largest number if you sort the digits, from largest to smallest.