With 123 digits you can make 123 one-digit numbers.
1,956 different numbers can be made from 6 digits. You can calculate this by using the permutation function in a summation function, like this: Σ6k=1 6Pk = 6P1+6P2+...+6P5+6P6 What this does is calculate how many 1 digit numbers you can make from 6 digits, then how many 2 digit numbers can be made from 6 digits and adds the amounts together, then calculates how many 3 digit numbers can be made and adds that on as well etc.
6 if all digits are different, 27 otherwise.
There are 5460 five digit numbers with a digit sum of 22.
The digits product of two digit has number four
5040 different 4 digit numbers can be formed with the digits 123456789. This is assuming that no digits are repeated with each combination.
You can make 4*4*4 = 64 numbers.
27 three digit numbers from the digits 3, 5, 7 including repetitions.
u culd make 80
If you want 4-digit numbers, there are 24 of them.
I take it that you want to make three digits numbers with 8,7,3, and 6 without repetition. The first digit cane be selected from among 4 digits, the second from 3 digits, the third digit from 2, hence the number of three digit numbers that can be formed without repetition is 4 x 3 x 2 = 24
There are 60480 numbers.
4! = 24 ■
None. 3 digit numbers are not divisible by 19 digit numbers.
6 2-digit numbers (13/15/35/53/51/31)
7 two-digit numbers.
Any pair of digits (not including 0), can be used to generate 14 four-digit numbers. If one of the digits is 0, only seven will start with a non-zero digit.
3*3*2*1 = 18 of them.
There are 5760 such numbers.
It can have 4 digits, because the highest possible two digit numbers 99*99=9801.
There are six choices, the 5 digits and the one you leave blank. That makes 6! or 720 different numbers.
There are 5*4*3 = 60 such numbers.
from 3 digits (10x10) to 4 digits (99X99)