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There are 9 choices for the first digit, 8 for the second, 7 for the third, and 6 for the last.

So there are 9x8x7x6=3024 "permutations"

That means the order does matter.

If the order does not matter, divide that number by 4!=4x3x2x1

9C4 is 126

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Q: How many 4 number combinations can you make with numbers 1-9 and without having any repeating numbers?
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