Best Answer

There are 9 1-digit numbers and 16-2 digit numbers. So a 5 digit combination is obtained as:

- Five 1-digit numbers and no 2-digit numbers: 126 combinations
- Three 1-digit numbers and one 2-digit number: 1344 combinations
- One 1-digit numbers and two 2-digit numbers: 1080 combinations

This scheme does not differentiate between {13, 24, 5} and {1, 2, 3, 4, 5}. Adjusting for that would complicate the calculation considerably and reduce the number of combinations.

🙏

🤨

😮

Study guides

☆☆

Q: How many 5 digit combinations for numbers 1- 25?

Write your answer...

Submit

Still have questions?

Related questions

There are 480,700 combinations and I am not going to even try to list them!

Their is 25 combinations

25

25=20,21,23

-22

There are 36 such numbers.There are 36 of them.

25 of them

6

5*4*3*2*1 = 120 combinations. * * * * * No. The previous answerer has confused permutations and combinations. There are only 25 = 32 combinations including the null combinations. There is 1 combination of all 5 numbers There are 5 combinations of 4 numbers out of 5 There are 10 combinations of 3 numbers out of 5 There are 10 combinations of 2 numbers out of 5 There are 5 combinations of 1 numbers out of 5 There is 1 combination of no 5 numbers 32 in all, or 31 if you want to disallow the null combination.

25

16, 25, 34, 43, 52, 61, 70 Seven of them.

Assuming you meant how many combinations can be formed by picking 8 numbers from 56 numbers, we have:(56 * 55 * 54 * 53 * 52 * 51 * 50 * 49)/8! = (7 * 11 * 3 * 53 * 13 * 51 * 25 * 7) = 1420494075 combinations. (Also equal to 57274321104000/40320)

about... 25 just take 5 numbers times 5 numbers

If the numbers are all different, then 25C5 = 25*24*23*22*21/(5*4*3*2*1) = 53,130.

It appears 25 times.

25 and 49

There are 25 such numbers.

Total number of 2-digit numbers = (99 - 9) = 90 of themEvery number that isn't a perfect square has an even number of factors.2-digit numbers that are perfect squares: 16, 25, 36, 49, 64, and 81 = 6 of themRemaining 2-digit numbers = (99 - 6) = 93 .

If each number is different from all of the other numbers and the combinations are considered distinct unless they contain the same numbers in the same order, the answer is 25 X 24 X 23 X 22 X 21 = 6,375,600. If the combinations are distinct only if they do not contain the same numbers, irrespective of order, then the answer is (25 X 24 X 23 X 22 X 21)(5 x 4 x 3 x 2) = 53,130.

There are 25 possibilities fitting those rules.

If the two must be different digits, then there 20 possibilities. If they can be the same one, then there are 25 possibilities.

22, if leading 0s are disallowed. 24 if they are permitted.

25 and 36 are each equal to their rightmost digit squared. 25 = 5 X 5 36 = 6 X 6

25 different combinations.

25 digit numbers would be septillions.