Best Answer

There are 9 1-digit numbers and 16-2 digit numbers. So a 5 digit combination is obtained as:

- Five 1-digit numbers and no 2-digit numbers: 126 combinations
- Three 1-digit numbers and one 2-digit number: 1344 combinations
- One 1-digit numbers and two 2-digit numbers: 1080 combinations

This scheme does not differentiate between {13, 24, 5} and {1, 2, 3, 4, 5}. Adjusting for that would complicate the calculation considerably and reduce the number of combinations.

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Q: How many 5 digit combinations for numbers 1- 25?

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6

The sum you require is 4!/2!2!, which is 6. This means there are 6 different two-digit numbers. * * * * * Wrong! The above formula is for the number of combinations, not permutations. However, since the number 23 is different from the number 32, you require permutations and not combinations. There are 4*3 = 12 23, 25, 27, 32, 35, 37, 52, 53, 57, 72, 73, 75.

17,576 possible combinations * * * * * Not quite! This is the total number of permutations of 3 letters out of 26. AAB is counted as being different from ABA or BAA. But these are the same combinations. Thus there are 26 combinations of just one letter. 26*25 combinations of two letters and 26*25*24/(3*2*1) of three. In all, that makes 26 + 650 + 2600 = 3276

quadrillion

The middle mber becomes the primary. Sort by that and then sort by the numbers to the left and then the numbers to the right. Example: 12-34-56 98-76-54 11-22-33 21-25-33 23-25-33 becomes: 11-22-33 21-25-33 23-25-33 12-34-56 98-76-54 Easy Schmeezy!

Related questions

There are 480,700 combinations and I am not going to even try to list them!

Their is 25 combinations

25

25=20,21,23

-22

There are 36 such numbers.There are 36 of them.

25 of them

6

5*4*3*2*1 = 120 combinations. * * * * * No. The previous answerer has confused permutations and combinations. There are only 25 = 32 combinations including the null combinations. There is 1 combination of all 5 numbers There are 5 combinations of 4 numbers out of 5 There are 10 combinations of 3 numbers out of 5 There are 10 combinations of 2 numbers out of 5 There are 5 combinations of 1 numbers out of 5 There is 1 combination of no 5 numbers 32 in all, or 31 if you want to disallow the null combination.

25

16, 25, 34, 43, 52, 61, 70 Seven of them.

Assuming you meant how many combinations can be formed by picking 8 numbers from 56 numbers, we have:(56 * 55 * 54 * 53 * 52 * 51 * 50 * 49)/8! = (7 * 11 * 3 * 53 * 13 * 51 * 25 * 7) = 1420494075 combinations. (Also equal to 57274321104000/40320)

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