0
How many numbers consisting of two digits can be formed from 2 3 5 7 IF Each integer is to be used only once?
The sum you require is 4!/2!2!, which is 6. This means there are 6 different two-digit numbers.
* * * * *
Wrong! The above formula is for the number of combinations, not permutations. However, since the number 23 is different from the number 32, you require permutations and not combinations.
There are 4*3 = 12
23, 25, 27,
32, 35, 37,
52, 53, 57,
72, 73, 75.
What else can I help you with?
How many 4 digit numbers can be formed from the digits 7341 if none of the digits can be repeated?
24
How many 3 digit numbers can be formed from the digits 357 with any digit repeated?
27 three digit numbers from the digits 3, 5, 7 including repetitions.
How many 4 digit numbers can be formed by the digits 5 6 7 8?
24
How many odd four digit numbers can be formed from the digits 1 2 3 and 4?
128
How many 4 digit numbers can be formed using the digits 0 1 2 3 4 5 6 if repetitions of digits are allowed?
2,401
How many numbers consisting of two digits can be formed from 2 3 5 7 Each integer is to be used only once?
There are 4*3 = 12 such numbers.
How many 4 digit numbers can be formed from digits 123456789?
5040 different 4 digit numbers can be formed with the digits 123456789. This is assuming that no digits are repeated with each combination.
How many 5 digits numbers can be formed using digits?
99999
How many digits numbers each less than 500 can be formed from the digits 13467 if repetitions is allowed?
There are 5 numbers of 1 digit, 25 numbers of 2 digits, and 75 numbers of 3 digits. This makes 105 numbers in all.
How many 4 digit numbers can be formed from the digits 7341 if none of the digits can be repeated?
24
How many 5 digit numbers can be formed from the digits 012 if any of the digits can be repeated?
500
How many numbers of at least tree different digits can be formed from the integers 123456?
Numbers formed should be of at least 3 digits means they may be of 3 digits, 4 digits, 5 digits or 6 digits. There are 6 choices for digit in the units place. There are 5 and 4 choices for digits in ten and hundred’s place respectively. So, total number of ways by which 3 digits numbers can be formed = 6.5.4 = 120 Similarly, the total no.of ways by which 4 digits numbers can be formed = 6.5.4.3 = 360. the total no. of ways by which 5 digits numbers can be formed = 6.5.4.3.2 = 720. The total no.of ways by which 4 digits numbers can be formed = 6.5.4.3.2.1 = 720. So, total no.of ways by which the numbers of at least 3 digits can be formed = 120 + 360 + 720 + 720 = 1920.
How many 4 digit numbers can be formed from the digits 1234567 with no duplicate numbers?
840
How many 6 digit numbers can be formed using the digits 123456789?
There are 60480 numbers.
How many 3 digit numbers can be formed from the digits 12345 if the digits cannot be repeated?
1 set
The total number of five digit numbers that can be be formed digits 12345 is?
It is 120 if the digits cannot be repeated.
What is the biggest integer of the numbers 3 7 6 0 4?
Assuming the question requires the biggest number formed using the given digits - rather than applying mathematical operations to them - the answer is 76430.
