55C6 = 28,989,675
There are 11C2 = 11*10/(2*1) = 55 combinations.
55C6 = 28,989,675
There are 59C5 = 59*58*57*56*55/(5*4*3*2*1) = 5,006,386 combinations.
There are 56C5 = 56*55*54*53*51/(5*4*3*2*1) = 3,819,816 combinations.
There are 59C5 = 59*58*57*56*55/(5*4*3*2*1) = 5,006,386 combinations.
There are 11C2 = 11*10/(2*1) = 55 combinations.
55C6 = 28,989,675
There are 56C5 = 56*55*54*53*51/(5*4*3*2*1) = 3,819,816 combinations.
There are 59C5 = 59*58*57*56*55/(5*4*3*2*1) = 5,006,386 combinations.
There are 59C5 = 59*58*57*56*55/(5*4*3*2*1) = 5,006,386 combinations.
just intrested in the number combinations * * * * * Number of combinations = 56C6 = 56*55*54*53*52*51/(6*5*4*3*2*1) = 32,468,436
The number of combinations is nCr = (59*58*57*56*55)/(5*4*3*2*1) = 5006386
59! / 54! = 59 * 58 * 57 * 56 * 55 = 600766320
The answer is 55!/[(55-6)!*6!] where n!, or "n factorial" is n*(n-1)*(n-2)*...*2*1 So, in this case the answer simplifies to 55*54*53*52*51*50/[6*5*4*3*2*1] = 28,989,675
295 * * * * * Seriously underestimated! The correct answer is 59C5 = 59*58*57*56*55/(5*4*3*2*1) = 5,006,386
Number of combinations = 59*58*57*56*55/(5*4*3*2*1) = 5006386.
There are 6C3 = 20 such combinations.