295
* * * * *
Seriously underestimated!
The correct answer is 59C5 = 59*58*57*56*55/(5*4*3*2*1) = 5,006,386
There are 5,461,512 such combinations.
There are infinitely many numbers and so infinitely many possible combinations.
10.
There are 120 permutations and 5 combinations.
120 WRONG! That is the number of PERMUTATIONS. In the case of combinations, the order of the numbers does not matter, so there is only 1 5-number combination from 5 numbers.
There are 5,461,512 such combinations.
There are infinitely many numbers and so infinitely many possible combinations.
10.
You can make 5 combinations of 1 number, 10 combinations of 2 numbers, 10 combinations of 3 numbers, 5 combinations of 4 numbers, and 1 combinations of 5 number. 31 in all.
There are 120 permutations and 5 combinations.
120 WRONG! That is the number of PERMUTATIONS. In the case of combinations, the order of the numbers does not matter, so there is only 1 5-number combination from 5 numbers.
120 5x4x3x2x1=120
The answer is 31C5 = 31!/[26!5!] = 169,911
There are a huge number of combinations of 5 numbers when using the numbers 0 through 10. There are 10 to the 5th power combinations of these numbers.
Assuming there are 5 check boxes and the respondent may check any number of them, the answer is 25 = 32 combinations.
To find the number of 5-number combinations from the numbers 1 to 50, you can use the combination formula ( C(n, r) = \frac{n!}{r!(n-r)!} ). Here, ( n = 50 ) and ( r = 5 ). Therefore, the number of combinations is ( C(50, 5) = \frac{50!}{5!(50-5)!} = \frac{50!}{5! \times 45!} = 2,118,760 ). Thus, there are 2,118,760 different 5-number combinations possible.
Only one.