How many 6 number combinations in 55numbers?

Answer 1

The answer is 55!/[(55-6)!*6!]

where n!, or "n factorial" is n*(n-1)*(n-2)*...*2*1

So, in this case the answer simplifies to 55*54*53*52*51*50/[6*5*4*3*2*1]

= 28,989,675