The formula you are looking for is I = W/E.
Depends completely on the input voltage as watts is simply amps X volts. Assuming household of 120V or 240V would give an amperage of 3.33 A or 1.66A respectively
P= i * e
400w= i * 220v
i=1.8a
It will take 1.82 Amperes approximately.
draw 0.104 amps
The equation that you are looking for is I = E/R. Amps = Voltage/Resistance in ohms.
Depends on the size of the LED light and the voltage applied. An example is an LED 24 volt globe light that pulls 8 watts which draw 0.333333 amps. Take an LED 120 volt light bulb draws 12 watts and will pull 0.1 amps. The same bulb at 240 volts wil draw 0.05 amps. it really depends on the watts and voltage applied. An average would be about 0.1 amps.
1100 watts or about ten amps then another 3 to 4 amps for turn table light and fan
A 65 Watt incandescent light bulb should draw 65W/120V = 541.67mA
It depends on the draw of the compressor.
draw 0.104 amps
About 0.6 amps for a 12v 21w bulb
The equation that you are looking for is I = E/R. Amps = Voltage/Resistance in ohms.
Depends on the size of the LED light and the voltage applied. An example is an LED 24 volt globe light that pulls 8 watts which draw 0.333333 amps. Take an LED 120 volt light bulb draws 12 watts and will pull 0.1 amps. The same bulb at 240 volts wil draw 0.05 amps. it really depends on the watts and voltage applied. An average would be about 0.1 amps.
1100 watts or about ten amps then another 3 to 4 amps for turn table light and fan
1100 watts or about ten amps then another 3 to 4 amps for turn table light and fan
A 65 Watt incandescent light bulb should draw 65W/120V = 541.67mA
5500Watts/220V=25 Amps
Have to know the wattage or resistance of the lamp to answer this question.
If the light is operating at 110 volts, and P = I x E, then I = 300/110, or 2.5 amps.
A2.2 kW kettle will draw 9.16 amps at 240 volts. I = W/E. Amps = Watts/Volts.