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A perfect typical D cell is 1.5V (alkaline slightly less) so two cells are 3.0V. The current flow would follow Ohm's law E=I*R or in this case I (current) = E (voltage) / R (resistance) or 3/4 = 0.75 Amps.

Note that D-cells cannot for long supply this much current and the voltage from the cells will be less than 1.5V (due to the cell's internal resistance) and will fall off rapidly as they simply do not have the capacity to deliver this much current for very long.

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Q: How many amps in a circuit with 2 D cells and a resistance of 4 ohms?
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