There is insufficient information to be able to answer the question. It is not clear whether the left hand is angled at 75 deg above the the horizontal, below the horizontal or at 75 deg to the vertical. This, and the length of the left arm determines how high the balls are when they are caught and so how much time they spend in the air.
Let the angle = θLet the height = aLet the base = b* means multiplied byIf the angle touches the base:tanθ = a/bb = a/tanθIf the angle touches the height:tanθ = b/ab = a*tanθWhen transferring the second line of working (b= ...) into a calculator, replace a with the height and θ with the angle. The answer will be b.
You have to use trig. If the base angle is a and base b, the height is b tan(a).
Pull your wagon on a straight angle. Easy as that! :D
if you have a right angle and the other called fe is 14ft then what is fd?
Every degree of angle divides into 60 minutes of angle and every minute of angle divides into 60 seconds of angle. This system of measuring angles has been used since the Babylonians established it roughly 3000 years ago..
Each angle minute is divided into 60 seconds.
One degree of angle is equal to 3,600 seconds of angle.
52.22sec
Height will be h=base*tan(angle).
Depends on the angle between the side and the base. The smaller the angle the larger the height.
Height, angle, and track type. Height, angle, and track type.
Rotate handle
Assuming you know the angle of ascension, and the base, you can calculate the height by recalling that tangent theta is height over base. Simple algebra from there: height is tangent theta times base.
Let the angle = θLet the height = aLet the base = b* means multiplied byIf the angle touches the base:tanθ = a/bb = a/tanθIf the angle touches the height:tanθ = b/ab = a*tanθWhen transferring the second line of working (b= ...) into a calculator, replace a with the height and θ with the angle. The answer will be b.
h=u^2 sin^2x / 2g . where x is angle of release and h is the height of the projectile.
You have to use trig. If the base angle is a and base b, the height is b tan(a).
The height is a perpendicular angle from the base. The sides of the parallelogram are slanted tho and this will vary for every parallelogram. To find the height you typically make a triangle with one of the slanted sides.