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How many bits would you borrow to subnet 192.168.50.0 do to ten networks?
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What is the second subnet of 172.16.0.0?
172.16.0.0/16 gives you 65534 possible hosts within 1 subnet. By binary math, you would need to increase the subnet mask to divide the network into subnets. Think of the additional subnet mask bits as a binary value. With 0 extra bits in the masks, you have 1 subnet. With 1 bit, you have 2. With 2 bits, you have 4. With 3 bits, you have 8. With 4 bits, you have 16. We need 8, so we should add 3 bits to the subnet mask. This would be a base CIDR of 172.16.0.0/19. Since there are 256 possibilities in the 3rd octet (Based on Class B network), divide by 8. The resultant number is the increment value for each network address. 256 / 8 = 32. Therefore, your networks would be: 172.16.0.0/19 172.16.32.0/19 172.16.64.0/19 172.16.96.0/19 172.16.128.0/19 172.16.160.0/19 172.16.192.0/19 172.16.224.0/19 With maximum (65536 / 8 - 2) 8190 hosts per subnet. Additional: Since we have 19 network bits, there are 13 bits remaining for hosts (total, as always 32). An all 0 string of host bits would leave you with your base network number ex> 172.16.0.0/19 , host with all 0's 10101100.00010000.00000000.00000000 The resultant would be 172.16.0.0, which is your network address. Conversely, having a host with all 1's: 10101100.00010000.00011111.11111111 This would result in 172.16.31.255, which is the broadcast address for the first subnet. These aren't usable as assignable addresses, but are used for network and broadcast purposes. Using all of the 3 borrowed bits in a 111 situation gives you a resultant of 172.16.224.0/19, which is a legitimate network address. Network bits in this case carry over from the /16, and are simply added on. An IP address of 172.16.255.255 would be the broadcast address for the final subnet. ex> 10101100.00010000.11111111.11111111 If you were doing a class A network, this wouldn't be as applicable. If all 3 of the first bits of a network address are 1, this puts your IP into a class D (224.0.0.0/4) subnet which is reserved for multicasting. This is only applicable to the first bits of the network address (starting from the very beginning). Hope this helped at least a little.
When doing subtraction why would we have to borrow?
Becaue you can't remove, say, 4 cookies from 3. All this means is that if you have a bigger number and you need to subtract it form a smaller number you will need to borrow.
If you were to borrow twenty-five thousand dollars at a 10 percent interest for 36 months what would be your monthly payment?
763.89
What is the difference between Cat 2 verses cat 3 cable?
Cat 2 cable was rated at 4 or 16 mbps whereas cat 3 cable would be rated at 10 mbps. Since 10baseT networks with Ethernet ran at 10 mbps this meant that cat 2 cable would not be useable in those networks. The minimum category cable for those networks had to be at least a cat 3 cable.
In which of the following situations would you use rdp?
Network+ Guide to Networks answer: To enable someone else to control your workstation, which is running a Windows operating system.
How many would you borrow to subnet 192.168.50.0 down to at least 10 networks?
4 bits
How many bits would you borrow to subnet 172.16.100.0 to have at least 500 hosts?
we need to borrow 7 bits to subnet 172.16.100.0 to have at least 500 hosts and the subnet mask will be 255.255.254.0
What is the maximum number of bits that can be borrowed to create a subnet for a Class C network?
You can borrow 6 bits. Which would create a 255.255.255.252 subnet mask, but this subnet only contains 2 usable IP addresses. 7 bits would be 255.255.255.254, but that subnet is too small to have any use in the real world.
What would someone use a subnet mask calculator for?
Someone would use a subnet mask calculator for splitting a network into sub networks. It is sometimes used to ease congestion on a network and divert traffic.
What is the default subnet mask for ip address 192.168.1.254?
That would be a class E network, E networks do not have defines subnet masks or networks. Just a range (240.0.0.0 - 255.255.255.255).
What is a subnet in computer networks?
A portion of a network that shares a common address component. On TCP/IP networks, subnets are defined as all devices whose IP addresses have the same prefix. For example, all devices with IP addresses that start with 100.100.100. would be part of the same subnet. Dividing a network into subnets is useful for both security and performance reasons. IP networks are divided using a subnet mask.
What is the maximum number of bits that can be borrowed with class b?
The maximum number of host bits that can be borrowed from a class A address is 22 (technically you could borrow 23 but the resulting network would be useless). A class A address uses 8 bits for its network address and 24 bits for its host addresses. Class A uses a subnet mask of 255.0.0.0 You can only borrow 22 bits (instead of 24) because a valid network requires 4 addresses: A network address, two host addresses and a broadcast address. These networks would result in 30 bits used for the network address and 2 bits used for the host addresses. These networks use a subnet mask of 255.255.255.252
Broadcast ip for 192.168.1.0?
You would also have to know the subnet mask.You would also have to know the subnet mask.You would also have to know the subnet mask.You would also have to know the subnet mask.
What is the network IP of 170.3.24.14 host IP?
It depends on your subnet mask. IP addresses begining with 170 are Class-B networks and if your using classful network boundries, then the network would be 170.3.0.0. But, its unlikely you're using classful boundries these days. The most common subnet uses a 24-bit subnet mask (255.255.255.0). It that's the case, then the network would be 170.3.24.0 There are of course other possibilites- everything depends on the subnet mask.
What is the subnet of 66.237.178.241?
The default subnet would be 255.0.0.0 (class A)
Which portion of the IP address 175.124.35.4 represents the host?
depends on the subnet mask ie/ 255.255.255.252 which would mean 175.124.35.0,4,8,12,16etc etc are networks and 175.124.35.1 & .2 are hosts. .3 is the broadcast address for that subnet.
Given class C address with a default subnet mask How many possible subnets and usable hosts if 4 bits were borrowed?
that gives you 16 subnets with 14 usable IPs for hosts that is because one is for subnet and one for broadcas in that subnet for example: 192.168.1.0/28 - subnet number 192.168.1.15 -broadcast number usable IPs for hosts - IPs between them that is 14
