Q: How do you solve x squared minus 4 equals zero?

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X=1

It can be solved by using the quadratic equation formula.

That factors to (x + 1)(x - 3) x = -1, 3

Zero minus zero equals zero.

Factor it. (x - 8)(x - 2) x = 2, 8

0 squared is 0. Zero times zero equals zero.

It Equals 2

It can't be solved because the discriminant of this quadratic equation is less than zero

Without knowing what "x" is, we cannot say what the answer will be. And without knowing the answer, we cannot solve for "x". Set x at zero, for example. Zero squared is zero, plus 6 time zero which is zero, minus 55. Your answer is then -55. Set x at one, for example. One squared is one, plus 6 times 1 which is six, minus 55. Your answer is then -48. Etc.

It equals 0. Zero times zero equals zero.

zero

x = 5 / 6squared + 7

Without that other number, all you've got is zero.

It equals 1

x2-2x+1 = 0 (x-1)(x-1) = 0 x = 1 and also x = 1

five one six minus one six equals five zero zero

17 minus 17 equals zero

x = 1

It is, as stated, x2 - 5x + 25/4 = 0

Quadratic formula gives roots as 1.53 and 10.47 (to nearest hundredth.)

Any number minus itself equals zero. Any number plus its opposite equals zero. Any number times zero equals zero.

I'll assume that's - 5c. Then you're looking for numbers that multiply to -24 and add to -5. That's -8 and 3. (c - 8)(c + 3) = 0 c = 8, -3

It is, as stated, 2x2 + x - 1 = 0. That is the quadratic form.

4x2 - 20 = 0∴x2 - 5 = 0∴x2 = 5∴x = √5

Zero '0'

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