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ΔH = cmΔT

The change in heat = change in temperature (degrees C) . volume of the liquid (l) . heat capacity of the liquid

ΔH = 4.18 . 0.65 . 7

ΔH = 19kJ of heat

1 Calorie = 4.184 kJ

so 4.55 Calories are needed to heat 650g of water from 13°C to 20°C

but as some heat will be lost to the environment and there will be some incomplete combustion so you will need to burn more to see that actual change in temperature.

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Q: How many calories of heat are required to raise the temperature of 650g of water from 13.0 C to 20.0 C?
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