1 calorie is needed to raise 1 g of water 1 °C.
350 * 22 = 7700 calories ■
1 calorie is the energy required to raise 1 gram of water by 1 degree C. So it would take 5 calories to raise it by 5 degrees C.
The three measurements of heat are temperature, specific heat capacity, and heat capacity. Temperature measures the average kinetic energy of particles in a substance, while specific heat capacity is the amount of heat required to raise the temperature of a unit mass of a substance by one degree Celsius. Heat capacity is the total amount of heat required to raise the temperature of a substance by one degree Celsius.
Specific heat capacity is the amount of heat energy required to raise the temperature of one unit mass of a substance by one degree Celsius.
The answer is 4,18 joule.
Ice. For 6 gr of water and 8 deg C you need 6 x 8 = 48 calories For 5 gr of ice and 20 deg C you need at least 100 ( 5 x 20) if we neglect small difference in the specific heat of ice versus water. If the ice melts then you need additional thermal energy to break the hydrogen bonds in ice (melting thermal energy) so it is even more.
q (amt of heat) = mass * specific heat * temp. differenceThe specific heat of water is 1.00 cal/goC & the temperature difference is 70-30 = 40oCq = (105 grams)*(1.00 cal/goC)*(40oC)= 4,200 calories
1 calorie is the energy required to raise 1 gram of water by 1 degree C. So it would take 5 calories to raise it by 5 degrees C.
Specific heat capacity is the term that describes the amount of thermal energy required to raise the temperature of a substance by 1.0 degree Celsius.
A calorie is the amount of heat you need to raise the temperature of one gram of water by one degree Celsius. Assuming you are raising the temperature of the water from twenty degrees Celsius to ninety-nine degrees Celsius, it would take 20,000 calories. To calculate this, subtract 20 from 99. This is the amount of degrees you need to raise the temperature of the water by. Then multiply that number by 256, the amount of water in grams. You should get 20,244 calories. In significant digits, your answer should be 20,000 calories.
The specific heat capacity of water is 4.18 J/g°C. To calculate the energy required to raise 21 kg of water by 2 degrees Celsius, use the formula: Energy = mass x specific heat capacity x temperature change. Plugging in the values, the energy required is 21,084 Joules.
The amount of heat required to increase the temperature of the substance to 1 degree greater than that of the initial temperature of the body!
The specific heat capacity of water is 4.18 J/g°C. Using the formula Q = mcΔT, where Q is the heat energy, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature, we can calculate the heat energy as follows: Q = 15g * 4.18 J/g°C * 25°C = 1567.5 J. Therefore, 1567.5 Joules of heat energy will be required to raise the temperature of 15 grams of water by 25 degrees Celsius.
1,000 grams of water by 75 degrees Celsius
The amount of energy required to raise the temperature of 1 kg of water by 1 degree Celsius is approximately 4,186 Joules. Therefore, to raise the temperature by 2 degrees Celsius, you would need about 8,372 Joules of energy.
To raise the temperature of a substance, you need to calculate the heat energy using the specific heat capacity of the substance. Without knowing the specific heat capacity of the substance in question, it's not possible to determine the exact amount of energy required to raise the temperature from 30 to 45 degrees Celsius.
Q = m * c * ΔT Where: Q = total heat required m = mass of water (in grams) c = specific heat capacity of water (4.18 J/g°C) ΔT = change in temperature (final temperature - initial temperature)
Kilowatts is a unit of energy rate, while the temperature required to raise a specific volume of water by a specific amount of degrees is a unit of energy, not energy rate. The question cannot, therefore, be answered as stated. Please restate the question.