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How much heat is required to raise the temperature of 350 grams of water from 22 degrees C?
Wiki User
∙ 14y ago
1 calorie is needed to raise 1 g of water 1 °C.
350 * 22 = 7700 calories ■
Wiki User
∙ 14y ago
The specific heat capacity of water is 4.184 J/g°C. To raise the temperature of 350 grams of water from 22°C to a higher temperature, you would multiply the mass of water (350g) by the temperature change and the specific heat capacity of water. So, the heat required would be (350g) x (Tfinal - 22°C) x 4.184 J/g°C.
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How many calories are required to raise the temperature of 1 g of water by 5 degrees C?
It takes 1 calorie to raise the temperature of 1 gram of water by 1 degree Celsius. Therefore, to raise the temperature of 1 gram of water by 5 degrees Celsius, it would require 5 calories.
What are the 3 Measurements of Heat?
The three measurements of heat are temperature, specific heat capacity, and heat capacity. Temperature measures the average kinetic energy of particles in a substance, while specific heat capacity is the amount of heat required to raise the temperature of a unit mass of a substance by one degree Celsius. Heat capacity is the total amount of heat required to raise the temperature of a substance by one degree Celsius.
The amount of heat per unit mass required to raise the temperature by one degree Celsius is?
Specific heat capacity is the amount of heat energy required to raise the temperature of one unit mass of a substance by one degree Celsius.
Does it take more thermal energy to raise the temp of 6 grams of water by 8 degrees C or 5 grams of ice by twenty degrees C?
It takes more thermal energy to raise the temperature of 5 grams of ice by 20 degrees Celsius. This is because you need to first melt the ice, which requires additional energy (the latent heat of fusion) before you can raise the temperature of the resulting water.
How much heat would be required to raise the temperature of 17.8 g Ag by 22C?
The answer is 4,18 joule.
How many calories are required to raise the temperature of 105 grams of water from 30.0 degrees C to 70.0 degrees C?
q (amt of heat) = mass * specific heat * temp. differenceThe specific heat of water is 1.00 cal/goC & the temperature difference is 70-30 = 40oCq = (105 grams)*(1.00 cal/goC)*(40oC)= 4,200 calories
How many calories are required to raise the temperature of 1 g of water by 5 degrees C?
It takes 1 calorie to raise the temperature of 1 gram of water by 1 degree Celsius. Therefore, to raise the temperature of 1 gram of water by 5 degrees Celsius, it would require 5 calories.
What term describes the amount of thermal energy that is required to raise the temperature of a substance by 1.0 degrees Celsius?
Specific heat capacity is the term that describes the amount of thermal energy required to raise the temperature of a substance by 1.0 degree Celsius.
How many calories of heat would it take to raise the temperature of 256 grams of water from 20 degrees to 99 degrees?
A calorie is the amount of heat you need to raise the temperature of one gram of water by one degree Celsius. Assuming you are raising the temperature of the water from twenty degrees Celsius to ninety-nine degrees Celsius, it would take 20,000 calories. To calculate this, subtract 20 from 99. This is the amount of degrees you need to raise the temperature of the water by. Then multiply that number by 256, the amount of water in grams. You should get 20,244 calories. In significant digits, your answer should be 20,000 calories.
How much energy is required to raise 21kg of water by 2 degrees Celsius?
The specific heat capacity of water is 4.18 J/g°C. To calculate the energy required to raise 21 kg of water by 2 degrees Celsius, use the formula: Energy = mass x specific heat capacity x temperature change. Plugging in the values, the energy required is 21,084 Joules.
What is substances specific heat?
The amount of heat required to increase the temperature of the substance to 1 degree greater than that of the initial temperature of the body!
How much heat energy will be required to raise the temperature of 15 grams of water 25 degrees c?
The specific heat capacity of water is 4.18 J/g°C. Using the formula Q = mcΔT, where Q is the heat energy, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature, we can calculate the heat energy as follows: Q = 15g * 4.18 J/g°C * 25°C = 1567.5 J. Therefore, 1567.5 Joules of heat energy will be required to raise the temperature of 15 grams of water by 25 degrees Celsius.
How much energy would you use to raise temperature of kg of water by 2 degrees Celsius?
The amount of energy required to raise the temperature of 1 kg of water by 1 degree Celsius is approximately 4,186 Joules. Therefore, to raise the temperature by 2 degrees Celsius, you would need about 8,372 Joules of energy.
The amount of dietary Calories in one hard-boiled egg could raise the temperature of?
1,000 grams of water by 75 degrees Celsius
How many joules does it take to raise temperature from 30 degrees Celsius to 45 degrees Celsius?
To raise the temperature of a substance, you need to calculate the heat energy using the specific heat capacity of the substance. Without knowing the specific heat capacity of the substance in question, it's not possible to determine the exact amount of energy required to raise the temperature from 30 to 45 degrees Celsius.
In the space below show a numerical setup for calculating the total amount of heat required to raise the temperature of the H2O(l) from 0 degrees C to its final temperature?
Q = m * c * ΔT Where: Q = total heat required m = mass of water (in grams) c = specific heat capacity of water (4.18 J/g°C) ΔT = change in temperature (final temperature - initial temperature)
How many kilowatts are required to raise the temperature of 1000 liters of water by 10 degrees centigrade?
To raise the temperature of 1000 liters of water by 10 degrees Celsius, you would require approximately 239 kilowatt-hours of energy. This can be calculated using the specific heat capacity of water and the formula for calculating energy required for temperature change.
