If the order of the five in the set makes a difference, there are (25 x 24 x 23 x 22 x 21) = 6,375,600 sets.
If the order doesn't matter, then there are (25 x 24 x 23 x 22 x 21) / (5 x 4 x 3 x 2 x 1) = 53,130 sets.
In a set of 4 numbers, the number of combinations depends on how many numbers you want to choose from that set. If you want to choose all 4 numbers, there is only 1 combination. If you choose 2 numbers from the set, the number of combinations is calculated using the formula ( \binom{n}{r} = \frac{n!}{r!(n-r)!} ), which in this case would be ( \binom{4}{2} = 6 ). For different values of r (choosing 1, 2, or 3 numbers), the combinations would be 4, 6, and 4 respectively.
By making a number tree that could have as many as 1,000,000 combos.
Could you generate a complete set of 6 number combinations from 45 numbers ?
There are 5*5*5 = 125 such numbers.
86,450
41
If the numbers are allowed to repeat, then there are six to the fourth power possible combinations, or 1296. If they are not allowed to repeat then there are only 360 combinations.
By making a number tree that could have as many as 1,000,000 combos.
Could you generate a complete set of 6 number combinations from 45 numbers ?
There are 5*5*5 = 125 such numbers.
86,450
Oh, isn't that a happy little question? Let's see here... To find the number of combinations of 4 numbers out of 7, we can use a simple formula: 7 choose 4, which is calculated as 7! / (4! * (7-4)!). So, there are 35 unique combinations of 4 numbers that can be made from a set of 7 numbers. Isn't that just delightful?
375
25
The average is the sum of the numbers in the set divided by the number of numbers in the set. In this case it is (125+143+134)/3=134.
They are elements of the infinite set of numbers of the form 125*k where k is an integer.
It gives you the amounts of combinations of numbers from a set of numbers. For example if you wanted to find how many combinations of 2 numbers can you get from 6 numbers you would do this: =COMBIN(6,2) It will give the result 15, because there are 15 combinations as follows, where we are getting combinations of 2 numbers from the numbers 1 to 6: 1,2 1,3 1,4 1,5 1,6 2,3 2,4 2,5 2,6 3,4 3,5 3,6 4,5 4,6 5,6