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Q: How many combinations can you make with 7 12 5 and 3 objects?

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12 how come

Assuming that the only permitted operation is addition, then there are 4 combinations.

12

There are 24C12 = 24!/[12!*12!] = 2,704,156 combinations.

12 Combinations.

There are 24C12 = 24*23*...*13/(12*11*...*1) = 2,704,156 combinations.

26 = 64 combinations, including the null combination - which contains no numbers.

144 a gross = 12 dozen 12x12=144

You would get 4!/2! = 12 combinations.

32 combinations. 4 of these will have no toppings, or all three toppings, 12 will have one topping and another 12 will have 2 toppings.

Only three: 12, 13 and 23. Remember that the combinations 12 and 21 are the same.

30

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