Oh, what a happy little question! To find the number of combinations with the digits 1, 2, 4, and 8, you can use a simple formula. Since there are 4 digits, you can arrange them in 4! (4 factorial) ways, which is 4 x 3 x 2 x 1 = 24 combinations. Just imagine all the beautiful possibilities you can create with those numbers!
24 numbers
Yes, you can do 12 + 7 + 5 = 24
0.04
To find all the combinations of the numbers 1204 without repeating any number, we can use the formula for permutations without repetition. There are 4 digits in the number 1204, so there are 4 factorial (4!) or 24 possible combinations. These combinations would include 1204, 1240, 1024, 1042, 1402, 1420, 2104, 2140, 2014, 2041, 2401, 2410, 4012, 4021, 4102, 4120, 4201, 4210, 1024, 1042, 1204, 1240, 1402, 1420.
There are 24C12 = 24!/[12!*12!] = 2,704,156 combinations.
Well, honey, since you're picking 12 numbers out of 24, you're looking at a combination situation. The formula for combinations is nCr = n! / (r!(n-r)!), where n is the total number of items and r is the number of items you're choosing. So, in this case, it would be 24C12 = 24! / (12!(24-12)!). Plug that into a calculator, and you'll get your answer. Math can be a real hoot, can't it?
24C7 = 24!/((24-7)!7!) = 346,104.
4!=4x3x2x1=24
10 * * * * * That is just plain wrong! It depends on how many numbers in each combination but there are 1 combination of 4 numbers out of 4, 4 combinations of 3 numbers out of 4, 6 combinations of 2 numbers out of 4, 4 combinations of 1 number out of 4. A grand total of 15 (= 24-1) combinations.
24
It depends how many numbers are in your combinations: 0 or 24 there is 1 1 or 23 there are 24 2 or 22 there are 276 3 or 21 there are 2,024 4 or 20 there are 10,626 5 or 19 there are 42,504 6 or 18 there are 134,596 7 or 17 there are 346,104 8 or 16 there are 735,471 9 or 15 there are 1,307,504 10 or 14 there are 1,961,256 11 or 13 there are 2,496,144 12 there are 2,704,156 If by combinations you do not mean the mathematical selection of a subset of items from a set of items (where the order doesn't matter) but how many ways are there of arranging 24 numbers then there are: 24! = 620,448,401,733,239,439,360,000 ways.
1 and 11 and 21 and 31 and 42 and 12 and 22 and 32 and 43 and 13 and 23 and 33 and 44 and 14 and 24 and 34 and 416 combinations
There are 12 such numbers (excluding 24).
4! = 4*3*2*1 = 24 of them.
there are altogether 24 numbers between 9 and 32. by using nCr, 24C4 = 10626
it is hard to say there are lot of combinations belive or not * * * * * If the previous answerer thinks 15 is a lot then true. There are 1 combination of 4 numbers out of 4, 4 combinations of 3 numbers out of 4, 6 combinations of 2 numbers out of 4, 4 combinations of 1 number out of 4. A grand total of 15 (= 24-1) combinations. Not so hard to say!