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31C5 which is 31!/[5!*(31-5)!] = 31*30*29*28*27/(5*4*3*2*1)
= 169911
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∙ 12y ago
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How many combinations of 5 numbers are there in 31 numbers?
31C5 = 169911
How many combinations of 4 are there in 31 numbers?
we think its 3 comb.
How Many combinations can you come up with using 31 numbers and only 5 number combinations?
The answer is 31C5 = 31!/[26!5!] = 169,911
How many combinations of 3 numbers are there in 32 numbers what are these combinations?
There are 32C3 = 32*31*30/(3*2*1) = 4960 combinations. I do not have the inclination to list them all.
How many combinations can you make with the numbers 2 3 6 7 and 8?
You can make 5 combinations of 1 number, 10 combinations of 2 numbers, 10 combinations of 3 numbers, 5 combinations of 4 numbers, and 1 combinations of 5 number. 31 in all.
How many number combinations for the numbers 1 through four?
1 and 11 and 21 and 31 and 42 and 12 and 22 and 32 and 43 and 13 and 23 and 33 and 44 and 14 and 24 and 34 and 416 combinations
What two numbers make up 33?
There are many different combinations. One example is two and 31.
How many combinations are there with 5 numbers?
5*4*3*2*1 = 120 combinations. * * * * * No. The previous answerer has confused permutations and combinations. There are only 25 = 32 combinations including the null combinations. There is 1 combination of all 5 numbers There are 5 combinations of 4 numbers out of 5 There are 10 combinations of 3 numbers out of 5 There are 10 combinations of 2 numbers out of 5 There are 5 combinations of 1 numbers out of 5 There is 1 combination of no 5 numbers 32 in all, or 31 if you want to disallow the null combination.
How many combinations of 6 numbers are there in 42 numbers what are the numbers?
There are 5245786 possible combinations and I am not stupid enough to try and list what they are!
How many combinations of 6 numbers are there in 33?
There are 33C6 = 33*32*31*30*29*28/(6*5*4*3*2*1) = 1,107,568 combinations.
How many combination you can make from 2-6-11-19-25-31- 38?
Just one. When considering combinations, the order of the numbers makes no difference. So there is only one combination with those 7 numbers.
How many different combinations of coins total exactly 31 cents?
A lot
