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You have a three digit number that can only use each digit once in combination. Therefore, a number like 456 is acceptable, but 455 or 101 or 222 is not acceptable. I think you can solve the problem in the following manner. There are 10 possible digits (0-9) that can be used in the first number. For the second number there are only 9 possible since you cannot repeat one of the first. For the third number there are only 8 possible since again you cannot repeat any of the first two. You multiply the possibilities for each digit to get our answer. 10 * 9 * 8 = 720 There are 720 possible combinations.

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Q: How many combinations of three digits can be made using each digit only once in each combination?
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How many 3 digit combinations there 0-9?

The order of the digits in a combination does not matter. So 123 is the same as 132 or 312 etc. There are 10 combinations using just one of the digits (3 times). There are 90 combinations using 2 digits (1 once and 1 twice). There are 120 combinations using three different digit. 220 in all.


How many different combinations can you get from 1855?

Twelve in all: One of 4 digits, Three of 3 digits, Four of 2 digits, Three of 1 digit, and One with no digits. In mathematical terms, the last IS a combination, but in common usage, probably not.


What are the possible combinations for a lock with 3 wheels and the digits 0 to 9?

The short answer is 1000. This is very easy to visualise: Simply consider each number in the combination to be a digit in a decimal number. We then end up with a three-digit number. Such a three-digit number ranges in value from 000 to 999, or 1000 unique combinations.


How many different three digit combinations can be made from numbers 0 1 2 3 4 5 6 7 8 9?

There are 720 combinations if you use each of the digits only once per combination.


How many combination of three digits of 0-9 will add up to 10?

There are 13 combinations.


How many 3 digit combinations can be made from 0 to 6 digits?

I'll assume that you mean " ... from the digits 0, 1, 2, 3, 4, 5, and 6 ?" . -- If the same digit can appear more than once in the same combination, then there are (7 x 7 x 7) = 343 possibilities. -- If the three digits in one combination must all be different digits, then there are (7 x 6 x 5) = 210 possibilities. -- If the combinations are actual cou nting numbers, and so the first digit can't be 'zero', then there are (6 x 6 x 5) = 180 possibilities.


How many three digit combinations can be formed using 123456?

Assuming no repeated digits, lowest first, 20; in any order 120; Allowing repeated digits: 216


How many three-number combinations can be made from 551?

Only 1. In a combination, the order of the digits does not matter.


How many combination of three digits can be made from the number 0-9 that's larger than 15?

We notice that you said "combinations of three digits". You didn't say "3-digit numbers".There are (10 x 10 x 10) = 1000 combinations of three digits.The only combinations of 3 digits that form numbers less than 15 are 000, 001, 002, . . .012, 013, and 014. There are 15 of those.So the remaining (1000 - 15) = 985 are all larger than 15.


What are the combinations of the numbers 5 6 7?

How many digits are in each combination ? ? -- If one, then there are three combinations: {5}, {6}, and {7) . -- If two, then there are three combinations: {5, 6}, (5, 7), and {6, 7}. -- If three, then there is only one combination: {5, 6, 7}


How many one two or three digit combinations can you get using 1 2 and 3 in any one two or three configuration?

This question could would be best answered if you have a basic understanding of combinatorics (the study of combinations and permutations and probability) however, for something with as few possibilities as this, it is often easier to just make a list. Start with three digit combinations, then two digit combos, then one digit. Remember also that combinations are order independent ( ABC is the same thing as CBA) 3 digits 3 2 1 2 digits 3 2 3 1 2 1 1 digits 1 2 3 count those up and voila.


How many different 3 digit combinations can be made using 0 thru 9 and they can repeat?

Using the word "combinations" in the English sense (as opposed to mathematical sense the expert has used) where it often used in the mathematical sense of the word "permutations": Assuming the hundreds digit must be at least 1 (eg 99 = 099 is not considered a three digit number), then: 9 x 10 x 10 = 900.