The short answer is 1000. This is very easy to visualise: Simply consider each number in the combination to be a digit in a decimal number. We then end up with a three-digit number. Such a three-digit number ranges in value from 000 to 999, or 1000 unique combinations.
1000
10 possible numbers on each wheel equals 10x10x10 or 1000 combinations possible.
If the digits can repeat, then there are 256 possible combinations. If they can't repeat, then there are 24 possibilities.
10000
In most 3-number locks, each number ring offers a choice of 10 digits, from 0 to 9. I that case, there are 103 = 1000 combinations.
That dependsThat depends upon whether you are allowed to repeat numbers. If you are allowed to repeat, that means that all seven digits (say 1 through 7) can be used in each of the four positions of your combination, even if a digit has been used in another position. That means there are 7 x 7 x 7 x 7 = 74 = 2401 possible combinations for your lock. But if you are not allowed to repeat, that means that every time you pick a digit for one spot, there will be one less digit for the next, and one less for the next, and so on. So, the first number can have seven possibilities, the second can have six, the third can have five, and the last can have four possible digits. That means there are 7 x 6 x 5 x 4 = 840 possible combinations for your lock, only about a third as many.Check out the related link at MathsIsFun. It has very good information on this subject.* * * * *That is true for PERMUTATIONS, but not for combinations. In a combination, the order of digits does not matter so that 1234 is the same as 1342 or 4213 ext.As a result you have 7C4 = 7!/[4!*(7-4)!] = 7*6*5/(3*2*1) = 35 combinations - not 2401.Incidentally, nCr is the notation for the number of combinations of r objects taken from n objects - exactly what the question asked for.
10 possible numbers on each wheel equals 10x10x10 or 1000 combinations possible.
6,720 combinations.
If the digits can repeat, then there are 256 possible combinations. If they can't repeat, then there are 24 possibilities.
All the possible digits (10 of them; 0-9) are multiplied by themselves by the number of digits that can be shown in the lock. (3) This is 103, or 1,000. This certainly shows why guessing is not a good way to break into a numerical lock, especially since three is a rather low number of digits for one!
10000
I would have to say 10,000 possible combinations. (0000, 0001, 0002 through 9998, 9999)
10x9x9x9
Assuming each "digit" actually has 10 different states, there are one million combinations possible in a six-digit combination lock. However, many combination lock designs actually have fewer than 10 different states per "digit", resulting in far fewer actual combinations on such locks.
In most 3-number locks, each number ring offers a choice of 10 digits, from 0 to 9. I that case, there are 103 = 1000 combinations.
If you don't know the code to the combination lock then your stuffed. Just go through all the possible combinations and unlock it (only if its a 3/4 digit) On the other hand if you do know the code and want to change the lock, hold down the unlock button/lever and change the digits and that should change the code.
Assuming that repeated numbers are allowed, the number of possible combinations is given by 40 * 40 * 40 = 64000.If repeated numbers are not allowed, the number of possible combinations is given by 40 * 39 * 38 = 59280.
If you wish to use a brute-force method, assuming the digits go from 0 to 9 there are 10,000 possible permutations.