if you mean "vertices" by "corners" then sixteen
16
Corners
16
24 but note that if you piled the 3 cubes on top of eachother, you could make them into a single rectangular solid having only 8 corners.
A rectangular prism that is 4 cubes by 2 cubes is made up of 8 cubes.
2 cubes wide x 3 cubes long x 4 cubes high. 2 X 3 X4 6 X 4 24 cubes
A cube has 6 faces. It also has 12 edges and 8 corners. Cubes are a three dimensional structure.
They have 16 corners.
10 corners
2 sides, 2 corners. (:
I am assuming that your question states that the top and sides are painted red but the bottom isn't. If so, the answer is:- There are no cubes with 4 faces painted, the most that can be painted is 3 for the ones on the corners. There are 4 corners at the top of the cube that will have their top and 2 sides painted. Therefore there are 4 cubes with 3 painted. The cubes at the corners on the second and third row down will have 2 faces painted, as will the middle cubes on the top row so there are 12 of them in this puzzle. The cube in the middle of each painted face will have just one face painted so this is 5 (assuming the bottom isn't painted). The cubes in the middle of the bottom row will also have one face painted. This brings the total to 9 That is the total of cubes that have paint on them... 4+12+9 = 25 There are 27 cubes in your puzzle so only 2 have no painted faces. The cube right in the middle and the cube in the middle of the bottom layer.