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How many diagonals does an 11-sided polygon have?
An 11 sided polygon has 44 diagonals.
How many diagonals does a four-sided polygon have?
A four-sided polygon has two diagonals.
How many diagonals does a 14 sided polygon shape have?
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How many diagonals can be drawn in a 5-sided polygon?
A 5-sided polygon is called a pentagon. You can draw up to 5 diagonals in a pentagon.
How many diagonals does a 80 sided shape have?
To calculate the number of diagonals in an 80-sided polygon, you can use the formula: ( \frac{n(n - 3)}{2} ), where ( n ) is the number of sides. For an 80-sided polygon, this becomes ( \frac{80(80 - 3)}{2} = \frac{80 \times 77}{2} = 3080 ). Therefore, an 80-sided shape has 3,080 diagonals.
How many diagonals does an 11-sided polygon have?
An 11 sided polygon has 44 diagonals.
How many diagonals in a 15 sided polygon?
There are 90 diagonals in a 15-sided polygon.
How many diagonals does a four-sided polygon have?
A four-sided polygon has two diagonals.
How many diagonals does a 14 sided polygon shape have?
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How many diagonals are in a 7 sided polygon?
A 4-sided polygon has 2 diagonals. A 5-sided polygon, 5. 6-sided, 9. By induction, an n-sided polygon has 'n*(n-3)/2' diagonals. "n" is how many sides a shape has. so, (7)*(7-3)/2 now we have, 7*4/2 so, 28/2 = 14 Therefore, a 7-sided polygon would have 14 diagonals.
How many diagonals are in a10 sided polygon?
It has 35 diagonals
How many diagonals are in a 20 sided polygon?
There are 170 diagonals
How many diagonals does in a 3-sided polygon?
A 3-sided polygon is a triangle. There is no diagonal for that shape since all non-adjacent vertices share a line segment!
How many diagonals does a 100 sided polygon Have?
100 sided polygon has = n(n-3)/2 diagonals = 100(100-3)/2 = 4850 diagonals
How many diagonals can be drawn in a 5-sided polygon?
A 5-sided polygon is called a pentagon. You can draw up to 5 diagonals in a pentagon.
How many diagonals does a 80 sided shape have?
To calculate the number of diagonals in an 80-sided polygon, you can use the formula: ( \frac{n(n - 3)}{2} ), where ( n ) is the number of sides. For an 80-sided polygon, this becomes ( \frac{80(80 - 3)}{2} = \frac{80 \times 77}{2} = 3080 ). Therefore, an 80-sided shape has 3,080 diagonals.
How many diagonals does a 103 sided polygon have?
It works out as having 5150 diagonals
