100 sided polygon has = n(n-3)/2 diagonals = 100(100-3)/2 = 4850 diagonals
0.5*(1002-300) = 4850 diagonals
A regular 100-sided polygon has 4,850 diagonals. You can either check this for yourself, or use the formula provided in Related Questions below.
100*(100-3)/2 = 4850
It has: 0.5*(100^2-(3*100)) = 4850 diagonals
100 diagonals * * * * * No, it is 0.5*10*(10-3) = 35
98
There are: 0.5*(1002-(3*100)) = 4850 diagonals
In a 100-sided polygon, if diagonals are drawn from one vertex, they connect to all non-adjacent vertices. A vertex connects to 97 other vertices (100 total vertices minus the 1 vertex itself and the 2 adjacent vertices). The number of triangles formed with the diagonals from that vertex is given by the formula for combinations, specifically ( \binom{97}{2} ), which equals 4,656 triangles.
1/2*(1002-300) = 4850 diagonals
The name of a 100 sided polygon is Hectogon.
The name of a 100 sided polygon is Hectogon.
98