Sides: 8 Diagonals : 20
20 sides and 170 diagonals
20
20 sides 1/2*(202-60) = 170 diagonals
A polygon with n sides had n*(n-3)/2 diagonals. So a 20 sided polygon would have 20*17/3 = 170
It has 20 diagonals
A polygon with n sides has n*(n - 3)/2 diagonals. So n = 23 gives 23*20/10 = 230 diagonals
An octagon has 8 sides and 20 diagonals so the question doesn't make sense
0.5*(64-24) = 20 diagonals
A regular octogon (8 sides) has 20 diagonals. An irregular octogon also has 20 diagonals, but only if all its points point outwards.
Such a polygon does not exist. A polygon with n sides has 0.5*n*(n-3) diagonals If there are 10 diagonals then 0.5*n*(n-3) = 10 which requires n2 - 3n - 20 = 0 which has no integer roots.
There are 20 diagonals