170
Sides: 8 Diagonals : 20
20 sides and 170 diagonals
20
20 sides 1/2*(202-60) = 170 diagonals
A polygon with n sides had n*(n-3)/2 diagonals. So a 20 sided polygon would have 20*17/3 = 170
It has 20 diagonals
A polygon with n sides has n*(n - 3)/2 diagonals. So n = 23 gives 23*20/10 = 230 diagonals
An octagon has 8 sides and 20 diagonals so the question doesn't make sense
0.5*(64-24) = 20 diagonals
In geometry, a 20-diagonal refers to the number of diagonals in a polygon with 20 sides (20-gon). The formula to calculate the number of diagonals in a polygon with ( n ) sides is given by ( \frac{n(n-3)}{2} ). For a 20-gon, this results in ( \frac{20(20-3)}{2} = \frac{20 \times 17}{2} = 170 ) diagonals. Thus, a 20-gon has 170 diagonals.
An icosogon, which is a polygon with 20 sides, has a total of 170 diagonals. The formula to calculate the number of diagonals in a polygon is ( \frac{n(n-3)}{2} ), where ( n ) is the number of sides. For an icosogon, substituting ( n = 20 ) gives ( \frac{20(20-3)}{2} = \frac{20 \times 17}{2} = 170 ).
A regular octogon (8 sides) has 20 diagonals. An irregular octogon also has 20 diagonals, but only if all its points point outwards.