20
n is number of sides. Sum of interior angles is 180n - 360, so 180n = 2880 + 360, ie 3240 and n = 3240/180 ie 18.
To find the number of sides of a polygon given an interior angle, you can use the formula for the interior angle of a regular polygon: ( \text{Interior Angle} = \frac{(n-2) \times 180}{n} ), where ( n ) is the number of sides. Setting this equal to 3240 and solving for ( n ), we get: [ 3240 = \frac{(n-2) \times 180}{n} ] Multiplying both sides by ( n ) and rearranging gives ( n = 20 ). Therefore, the polygon has 20 sides.
All of the angles in an Iscosgon must add up too 3240
3240
3240 degrees
3240
20 sides
The formula for the sum of the interior angles for a polygon having n sides = 2n - 4 right angles. 3240 ÷ 90 = 36 right angles : When 2n - 4 = 36 then 2n = 36 + 4 = 40 : n = 20 The regular polygon has 20 sides.
The sum of the interior angles of a regular polygon can be calculated using the formula (n-2) * 180, where n is the number of sides. For a regular 20-sided polygon, the sum of the interior angles would be (20-2) * 180 = 3240 degrees.
20 sides
20
The 20 interior angles add up to 3240 degrees