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Any 3 from 10 in any order = 10 x 9 x 8 = 720
It depends on what other restrictions you place on the numbers. For example, in North America (country code +1 = USA, Canada, etc.), area codes cannot have 0 or 1 as the first digit, and cannot have 9 as the second digit.

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Q: How many different 3-digit codes can be created if no digit can be repeated?
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Related questions

How many different 4-digit codes can be created if no digit can be repeated?

Any 4 from 10 in any order = 10 x 9 x 8 x 7 = 5040


How many different 3 digit area codes can be created if no digit can be repeated?

The answer is 720 different area codes. This is how you calculate it. There are 10 different numbers for the first category, then 9 for the second and 8 for the third, then you multiply those numbers in this order: 10 x 9=90, then 90 x 8=720.


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Maths Problem Banks issue customers with 4 digit Pin Code numbers however the PIN codes have to have a pair of repeated digits 0889 6647 but not 3453 or 4444 how many codes are there?

the repeated digits can lie in any of 3 positions:XXYZ,YXXZ, or YZXXTherefore, the number of different possible repeated digit combinations is 10×3=30 (there are 10 different possible digits).There are then 9 values left that Y could be, after the X's have their values, and 8 values left that Z could be, to ensure no unintended repeated numbers.This gives (10×3)×9×8=2160. There are therefore 2160 possible codes.


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