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the repeated digits can lie in any of 3 positions:

XXYZ,YXXZ, or YZXX

Therefore, the number of different possible repeated digit combinations is 10×3=30 (there are 10 different possible digits).

There are then 9 values left that Y could be, after the X's have their values, and 8 values left that Z could be, to ensure no unintended repeated numbers.

This gives (10×3)×9×8=2160. There are therefore 2160 possible codes.

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Q: Maths Problem Banks issue customers with 4 digit Pin Code numbers however the PIN codes have to have a pair of repeated digits 0889 6647 but not 3453 or 4444 how many codes are there?
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