To find the number of different groups of 4 that can be made from 17 students, you can use the combination formula, which is given by ( C(n, r) = \frac{n!}{r!(n-r)!} ). In this case, ( n = 17 ) and ( r = 4 ). Therefore, the calculation is ( C(17, 4) = \frac{17!}{4!(17-4)!} = \frac{17!}{4! \times 13!} = \frac{17 \times 16 \times 15 \times 14}{4 \times 3 \times 2 \times 1} = 2380 ). Thus, there are 2,380 different groups of 4 that can be formed from 17 students.
if order does not matter then, (23x22x21x20x19)/(5x4x3x2x1) = 33,649
20 x 19 x 18/3 x 2 = 1,140 groups
There are only two possibilities... 10 groups of 2 or 5 groups of 4. Unless - you can have varying sized groups - which you didn't specify.
we can make 1 group
2 groups of 16, 4 groups of 8, 8 groups of 4, 16 groups of 2. Not really divided or in groups, but there could be 1 group of 32 or everyone by themselves.
30C8 = 5,852,925
if order does not matter then, (23x22x21x20x19)/(5x4x3x2x1) = 33,649
20 x 19 x 18/3 x 2 = 1,140 groups
There are 247 groups comprising 2 or more students.
mutlicellular
2.33333333
To divide a class of 32 students into groups with equal numbers of students, you would need to find the factors of 32. The factors of 32 are 1, 2, 4, 8, 16, and 32. Therefore, you can divide the class into 1 group of 32 students, 2 groups of 16 students, 4 groups of 8 students, 8 groups of 4 students, 16 groups of 2 students, or 32 groups of 1 student. So, there are 6 ways to divide the class into groups with equal numbers of students.
23 x 22 x 21 x 20/4 x 3 x 2 = 8,855 groups
they can be 2 groups of 16, 4 groups of 8, 8 groups of 4, or 16 groups of 2
17.0588
because the country is made up of people from many different backgrounds and groups
There are only two possibilities... 10 groups of 2 or 5 groups of 4. Unless - you can have varying sized groups - which you didn't specify.