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How many different groups of 3 students can be formed if there are 20 students in the class?
20 x 19 x 18/3 x 2 = 1,140 groups
How many three person relay teams can be chosen from six students?
two
How do you solve this combinations problem .There are 20 students in one class. They need to form groups of at least 2 people and at most 4 people. In how many different ways can they do that?
There are only two possibilities... 10 groups of 2 or 5 groups of 4. Unless - you can have varying sized groups - which you didn't specify.
How many different groups of 4 can be made from 17 students?
To find the number of different groups of 4 that can be made from 17 students, you can use the combination formula, which is given by ( C(n, r) = \frac{n!}{r!(n-r)!} ). In this case, ( n = 17 ) and ( r = 4 ). Therefore, the calculation is ( C(17, 4) = \frac{17!}{4!(17-4)!} = \frac{17!}{4! \times 13!} = \frac{17 \times 16 \times 15 \times 14}{4 \times 3 \times 2 \times 1} = 2380 ). Thus, there are 2,380 different groups of 4 that can be formed from 17 students.
How many ways can a committee of 3 students be chosen from a total count of 1514 students?
The first member chosen can be any one of 1,514 students.The second member chosen can be any one of the remaining 1,513 students.The third member chosen can be any one of the remaining 1,512 students.So there are (1,514 x 1,513 x 1,512) ways to choose three students.But for every group of three, there are (3 x 2 x 1) = 6 different orders in which the same 3 can be chosen.So the number of `distinct, unique committees of 3 students is(1514 x 1513 x 1512) / 6 = 577,251,864
How many different groups of 8 students can you create from a class of thirty students?
30C8 = 5,852,925
Is this a permutation In how many different ways could a committee of 5 students be chosen from a class of 25 students?
6,375,600
How many different groups of 3 students can be formed if there are 20 students in the class?
20 x 19 x 18/3 x 2 = 1,140 groups
How many ways can an adviser chosen 4 students from a class of 12 if they are given a different task?
There are 11880 ways.
How many ways can a committeee of 6 be chosen from 5 teachers and 4 students if the committee must includes three teachers and three students?
There are 10 different sets of teachers which can be combined with 4 different sets of students, so 40 possible committees.
How many groups can be formed from 8 students at least 2 at a time?
There are 247 groups comprising 2 or more students.
How many ways can a group of 3 students be chosen from a class of 30 students?
Well, honey, there are 30 students in the class, and you want to choose a group of 3. So, you're looking at a classic combination situation. The formula for combinations is nCr = n! / r!(n-r)!, so in this case, it's 30C3 = 30! / 3!(30-3)! = 4060 ways to choose those 3 lucky students. It's like picking the winning lottery numbers, but with fewer tears and more math.
35 coaches and 15 students split into groups. How many groups would they have?
2.33333333
How many different five-person relay teams can be chosen from 7 students?
Any 5 from 7 is (7 x 6)/2 ie 21.
How many three person relay teams can be chosen from six students?
two
How many groups of 5 basketball players can be chosen from a team of 12?
Two
How many different five-person relay teams can be chosen from 10 students?
C105 = 10 ! / (5!x(10-5)!) = 10! /5!2 = 252
