To find the number of different groups of 4 that can be made from 17 students, you can use the combination formula, which is given by ( C(n, r) = \frac{n!}{r!(n-r)!} ). In this case, ( n = 17 ) and ( r = 4 ). Therefore, the calculation is ( C(17, 4) = \frac{17!}{4!(17-4)!} = \frac{17!}{4! \times 13!} = \frac{17 \times 16 \times 15 \times 14}{4 \times 3 \times 2 \times 1} = 2380 ). Thus, there are 2,380 different groups of 4 that can be formed from 17 students.
if order does not matter then, (23x22x21x20x19)/(5x4x3x2x1) = 33,649
20 x 19 x 18/3 x 2 = 1,140 groups
The number of different groups of students that can be formed from 16 students depends on the size of the groups being formed. If you are looking for all possible combinations of groups of any size (from 1 to 16), you can use the formula for combinations. The total number of combinations would be (2^{16} - 1) (subtracting 1 to exclude the empty group), which equals 65,535 different groups. If you specify a particular group size, the calculation would be different.
To divide 32 students into groups with equal numbers of students, the group sizes must be divisors of 32. The divisors of 32 are 1, 2, 4, 8, 16, and 32. Therefore, the students can be grouped into 1 group of 32, 2 groups of 16, 4 groups of 8, 8 groups of 4, 16 groups of 2, or 32 groups of 1.
To find the number of different groups of 3 students that can be selected from 10 students, we use the combination formula: ( C(n, r) = \frac{n!}{r!(n-r)!} ). Here, ( n = 10 ) and ( r = 3 ), so the calculation is ( C(10, 3) = \frac{10!}{3!(10-3)!} = \frac{10 \times 9 \times 8}{3 \times 2 \times 1} = 120 ). Therefore, there are 120 different groups of 3 students that can be formed.
30C8 = 5,852,925
if order does not matter then, (23x22x21x20x19)/(5x4x3x2x1) = 33,649
20 x 19 x 18/3 x 2 = 1,140 groups
The number of different groups of students that can be formed from 16 students depends on the size of the groups being formed. If you are looking for all possible combinations of groups of any size (from 1 to 16), you can use the formula for combinations. The total number of combinations would be (2^{16} - 1) (subtracting 1 to exclude the empty group), which equals 65,535 different groups. If you specify a particular group size, the calculation would be different.
There are 247 groups comprising 2 or more students.
mutlicellular
2.33333333
To find the number of different groups of 3 students that can be selected from 10 students, we use the combination formula: ( C(n, r) = \frac{n!}{r!(n-r)!} ). Here, ( n = 10 ) and ( r = 3 ), so the calculation is ( C(10, 3) = \frac{10!}{3!(10-3)!} = \frac{10 \times 9 \times 8}{3 \times 2 \times 1} = 120 ). Therefore, there are 120 different groups of 3 students that can be formed.
23 x 22 x 21 x 20/4 x 3 x 2 = 8,855 groups
To divide a class of 32 students into groups with equal numbers of students, you would need to find the factors of 32. The factors of 32 are 1, 2, 4, 8, 16, and 32. Therefore, you can divide the class into 1 group of 32 students, 2 groups of 16 students, 4 groups of 8 students, 8 groups of 4 students, 16 groups of 2 students, or 32 groups of 1 student. So, there are 6 ways to divide the class into groups with equal numbers of students.
they can be 2 groups of 16, 4 groups of 8, 8 groups of 4, or 16 groups of 2
17.0588