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Assuming the the last part of the question is that the sequence may not END in 000, there are 2997 sequences.

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Q: How many different sequences of 4 digits are possible if the first digit must be 3 4 or 5 and if the sequence may not in 000?

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The one closest to the Middle if your sequence is of an even set of digits. The median will be a specific number if you have a sequence of odd digits.

The one closest to the Middle if your sequence is of an even set of digits. The median will be a specific number if you have a sequence of odd digits.

The question does not contain a sequence but a single large number whose digits are the digits of the sequence, 3n run together. There is only one number, not a sequence, so there is no nth term.

A computer is programmed to generate a sequence of three digits, where each digit is either 0 or 1, and each of these is equally likely to occur. Construct a sample space that shows all possible three-digit sequences of 0s and 1s and then find the probability that a sequence will contain exactly one 0.

9,876

Related questions

10 digits to select for the first number in the sequence 10 digits to select for the second number in the sequence for each possible option of 10 digits in the first slot in the sequence (10 * 10) 10 digits to select for the third number in the sequence for each possible option of 10 digits in the second slot for each possible digit in the first slot of the sequence (or more easily put, 10 possible digits for each of 100 potential first two number sequences) [10*10*10] etc.... =10 * 10 * 10 * 10 * 10 * 10 * 10 = 10^7 = 10,000,000 (10 Million) Now add an area code before that 7 digit phone number and you get 10 Billion combinations (of course there are exclusions such as any sequence starting in 911 would be prohibited which is a reduction of 10 million numbers itself - 911 000 0001, 911 000 0002, etc. There are many other exclusions as well such as can't start with 0 - this removes another 1 billion sequences)

if repeating is allowed... 36 (6x6, for the last two digits) If not, 6 (3x2, last two digits)

A computer is programmed to generate a sequence of three digits, where each digit is either 0 or 1, and each of these is equally likely to occur. Construct a sample space that shows all possible three-digit sequences of 0s and 1s and then find the probability that a sequence will contain exactly one 0.

A computer is programmed to generate a sequence of three digits, where each digit is either 0 or 1, and each of these is equally likely to occur. Construct a sample space that shows all possible three-digit sequences of 0s and 1s and then find the probability that a sequence will contain exactly one 0.

The one closest to the Middle if your sequence is of an even set of digits. The median will be a specific number if you have a sequence of odd digits.

Could it be check Digits?

The digits (5 4 3 2) can be arranged in (4 x 3 x 2 x 1) = 24 different sequences. If they're allowed to repeat in the same sequence, then there are (4 x 4 x 4 x 4) = 256 possibilities.

The question does not contain a sequence but a single large number whose digits are the digits of the sequence, 3n run together. There is only one number, not a sequence, so there is no nth term.

2 x 56.

9,876