10 digits to select for the first number in the sequence
10 digits to select for the second number in the sequence for each possible option of 10 digits in the first slot in the sequence (10 * 10)
10 digits to select for the third number in the sequence for each possible option of 10 digits in the second slot for each possible digit in the first slot of the sequence (or more easily put, 10 possible digits for each of 100 potential first two number sequences) [10*10*10]
etc....
=10 * 10 * 10 * 10 * 10 * 10 * 10 = 10^7 = 10,000,000 (10 Million)
Now add an area code before that 7 digit phone number and you get 10 Billion combinations (of course there are exclusions such as any sequence starting in 911 would be prohibited which is a reduction of 10 million numbers itself - 911 000 0001, 911 000 0002, etc. There are many other exclusions as well such as can't start with 0 - this removes another 1 billion sequences)
Number of 7 digit combinations out of the 10 one-digit numbers = 120.
18
The number of different 7 digit plates that can be formed where the digits are notrepeated and no zero appears as the first digit is: 544 320.Calculation:Number of different plates = 9 [9P6] = 9 [9!/(9-6)!] = 9x9x8x7x6x5x4 = 544 320.
The first 8 digit number is 10,000,000, the last is 99,999,999 which means there are 90,000,000 8 digit numbers
There are 210 4 digit combinations and 5040 different 4 digit codes.
Assuming the the last part of the question is that the sequence may not END in 000, there are 2997 sequences.
You have 2 choices for 20 times, so the number of sequences is 220 or 1048576.
There are infinitely many possible number sequences, and infinitely many numbers which can appear in those sequences. Any and every number can appear in a number sequence.
Number of 7 digit combinations out of the 10 one-digit numbers = 120.
9*106 or 9 million.
Three numbers can be arranged in 27 different sequences if repetition is allowed, and in 6 different sequences if it's not.
6
The number of six digit numbers that you can make from ten different digits ifrepetitions of same digit on the six digit number is allowed is 1 000 000 numbers(including number 000 000).If no repetitions of the the same digit are allowed then you have:10P6 = 10!/(10-6)! = 151 200 different six digit numbers(six digit permutations form 10 different digits).
18
Bank of America uses a nine digit number for their bank accounts. Each person has their own account and has different numbers.
The number of different 7 digit plates that can be formed where the digits are notrepeated and no zero appears as the first digit is: 544 320.Calculation:Number of different plates = 9 [9P6] = 9 [9!/(9-6)!] = 9x9x8x7x6x5x4 = 544 320.
There are 17 such numbers.