-3
Three distinct prime factors, eight total.
4,536 whole numbers or mixed numbers. 5,040 pure decimals.
Seven of them.
2240
-3
The word "numbers" consists of 7 distinct letters. The number of permutations of these letters is calculated using the factorial of the number of letters, which is 7!. Therefore, the total number of permutations is 7! = 5,040.
To find how many numbers less than 100 are the product of 3 distinct primes, we can consider combinations of distinct primes. The smallest three distinct primes are 2, 3, and 5, whose product is 30. The next combination, 2, 3, and 7, gives 42, and continues with combinations like 2, 5, and 7 (70) and 3, 5, and 7 (105, which exceeds 100). Thus, the valid products less than 100 are 30, 42, and 70, leading to a total of 3 such numbers.
The mean is the is the total of the numbers and then dividing by how many numbers.
Just 36.
It is the total sum of the numbers divided by how many there are
There are only 5 distinct combinations of 4 numbers.(1234, 1235, 1245, 1345, 2345) C = 5! / 4!But there are 120 distinct combinations in distinct order (i.e. 24 ways to order each abcd).abcdabdcacbdacdbadbcadcb
You add up all the numbers then divide by how many numbers you have total.