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Three distinct prime factors, eight total.
4,536 whole numbers or mixed numbers. 5,040 pure decimals.
Seven of them.
The word "numbers" consists of 7 distinct letters. The number of permutations of these letters is calculated using the factorial of the number of letters, which is 7!. Therefore, the total number of permutations is 7! = 5,040.
To find how many numbers less than 100 are the product of 3 distinct primes, we can consider combinations of distinct primes. The smallest three distinct primes are 2, 3, and 5, whose product is 30. The next combination, 2, 3, and 7, gives 42, and continues with combinations like 2, 5, and 7 (70) and 3, 5, and 7 (105, which exceeds 100). Thus, the valid products less than 100 are 30, 42, and 70, leading to a total of 3 such numbers.
To find how many counting numbers have four distinct nonzero digits that sum up to 11, we first identify all combinations of four distinct digits (from 1 to 9) that meet this criterion. The possible combinations of digits that add up to 11 are limited, and we can use combinatorial methods to list them. After identifying valid sets, we can calculate the permutations for each set (since the order of digits matters) to get the total count. Upon calculating, we find there are 24 valid combinations yielding 576 distinct numbers.
2240
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The mean is the is the total of the numbers and then dividing by how many numbers.
Just 36.
It is the total sum of the numbers divided by how many there are
There are only 5 distinct combinations of 4 numbers.(1234, 1235, 1245, 1345, 2345) C = 5! / 4!But there are 120 distinct combinations in distinct order (i.e. 24 ways to order each abcd).abcdabdcacbdacdbadbcadcb