If the numbers and letters can be repeated then there are 45,697,600 possible outcomes. If the letters and numbers can not be repeated there are 32,292,000 possible outcomes.
360; I think.
239,500,800 12!/2! * * * * * Actually, as the word "permutation" [not permutations] has 11 letters, the answer is 11!/2! = 19,958,400
There are 26 possible letters and 10 possible numbers. The number of license plates possible is then 26*26*10*10*10*10 = 6760000.
it is 26
If the numbers and letters can be repeated then there are 45,697,600 possible outcomes. If the letters and numbers can not be repeated there are 32,292,000 possible outcomes.
360; I think.
239,500,800 12!/2! * * * * * Actually, as the word "permutation" [not permutations] has 11 letters, the answer is 11!/2! = 19,958,400
There are 8 letters in "geometry", so there are 8! (factorial) ways to arrange them in different permutations. 8! = 40,320 permutations.
8 digits will generate over 40,000 permutations.
There are 26 possible letters and 10 possible numbers. The number of license plates possible is then 26*26*10*10*10*10 = 6760000.
Normally, there would be 5!=120 different permutations* of five letters. Since two of the letters are the same, we can each of these permutations will be duplicated once (with the matching letters switched). So there are only half as many, or 60 permutations.* (the correct terminology is "permutation". "combination" means something else.)
To calculate the total number of possible combinations for a license plate using 3 letters and 3 numbers, we need to multiply the number of options for each character position. For letters, there are 26 options (A-Z), and for numbers, there are 10 options (0-9). Therefore, the total number of combinations can be calculated as 26 (letters) * 26 (letters) * 26 (letters) * 10 (numbers) * 10 (numbers) * 10 (numbers) = 17,576,000 possible combinations.
it is 26
Permutation City has 310 pages.
I suspect that you want permutations rather than combinations. The permutation ABC is different from ACB, but they are both the same combination. There are 26*26*26*10*10 or 1,757,600 possible permutations of 3 letters followed by 2 numbers. But there are ten ways of arranging 3 letters and 2 numbers: eg LLLNN, LNLNL etc. All in all, therefore, 17,576,000 permutations. However, some letters are not used so as to avoid confusion between letters and numbers: eg 0 and O. Also, some sequences are not used because they form (or suggest) inappropriate words.
5!= 5*4*3*2*1= 120 ways