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How many distinguishable permutations can be made from the letters in the word gallipolis?
Wiki User
∙ 11y ago
In the word "gallipolis"
there are 10 letters (n =
10).
"l" appears 3 times (n1 =
3).
"i" appears 2 times (n2 =
2).
And 5 letters appear once (n3 =1, n4 =
1, n5 =1, n6 =1, n7 =1)
The number of permutations that can be made with these 10 letters is;
P =
n!/(n1!n2!n3!n4!n5!n6!n7!) =
10!/(3!∙2!∙1!∙1!∙1!∙1!∙1!) =
302 400
Wiki User
∙ 11y ago
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