48
24,2
12,2,2
6,2,2,2
3,2,2,2,2
48
16,3
8,2,3
4,2,2,3
2,2,2,2,3
48
12,4
6,2,4
3,2,2,4
3,2,2,2,2
48
8,6
4,2,6
2,2,2,6
2,2,2,3,2
None. 67 is prime.
There are Two factor trees for 20
The proof looks fairly complicated; if you want to try to understand it, you can find a discussion and proof (or outline of proof?) here: http://en.wikipedia.org/wiki/Fundamental_theorem_of_arithmetic
There are at least nine different factor trees for 2000, one for each of its non-trivial factor pairs. Eighteen, if you consider the reverse of each pair to be a separate pair. The important information to remember is that it doesn't matter what factor pair you choose to start the tree. But since, if done correctly, all the factor trees will have the same number of branches and arrive at the same factors for the bottom branch, it's a waste of time to write them all out. 2000 1000,2 500,2,2 250,2,2,2 125,2,2,2,2 25,5,2,2,2,2 5,5,5,2,2,2,2 2000 50,40 25,2,40 5,5,2,40 5,5,2,20,2 5,5,2,10,2,2 5,5,2,5,2,2,2
two numbers 46 and 23
An exponent tells how many times a number is used as a factor.
An exponent tells how many times a number is used as a factor.
Many people use factor trees.
The exponent tells you how many times a number or base is used as a factor.
yes because u can divie it into many factor that equal the same number
It's not possible to inventory the precise number of trees.
The process is known as prime factorization. There are many methods to notate this. Factor trees, rainbows, continuous division, Euclid's algorithm, etc.