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How many five digit numbers can be formed from the digits 0234 and 5 when repetition is allowed such the number formed is divisible by 2 or 5 or both?
Wiki User
∙ 12y ago
Since it must be a 5 digit number, range is
the numbers from 20000 to 55555
we will use multiplication rule to figure this out too.
If a number is divible by two, its last(ones place) digit is even. If it
is divisible by 5 its last(ones place) digit is zero or 5.
We don't give a rat's derriere what the other digits are
(for divisibility by two or five)
The number of ways to choose the ten thousands place
digit is 4
the number of ways to choose the thousands place digit
is 5
the number of ways to choose the hundreds place digit
is 5
the number of ways to choose the tens place digit
is 5
The number of ways to choose the ones place digit is
FOUR, since it must be 0,2,4,5 and not 3
use multiplication rule and solution is
4 x 5 x 5 x 5 x 4 = 2000
Wiki User
∙ 12y ago
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How many 13 digit numbers are possible by using the digits 12345 which are divisible by 4 if repetition of digits is not allowed?
If repetition of digits isn't allowed, then no13-digit sequencescan be formed from only 5 digits.
How many 3 digit numbers can be formed from the digits 1234?
64 if repetition is allowed.24 if repetition is not allowed.
How many 5 digits can be formed using the digits 0 2 3 4 5 when repetition is allowed that the number formed is divisible by 2 and 5 or both?
There are 2000 such numbers.
Where d represents a digit from 0 9 how many different ISBN numbers are possible if repetition of digits is allowed?
There are 10 to the 10th power possibilities of ISBN numbers if d represents a digit from 0 to 9 and repetition of digits are allowed. That means there are 10,000,000,000 ISBN numbers possible.
How man 7 digit combinations can be made using numbers 0 through 9?
10^7 if the repetition of digits is allowed. 9*8*7*6*5*4*3 , if the repetition of digits is not allowed.
How many 13 digit numbers are possible by using the digits 12345 which are divisible by 4 if repetition of digits is not allowed?
If repetition of digits isn't allowed, then no13-digit sequencescan be formed from only 5 digits.
How many 3 digit numbers can be formed from the digits 1234?
64 if repetition is allowed.24 if repetition is not allowed.
How many 5 digits can be formed using the digits 0 2 3 4 5 when repetition is allowed that the number formed is divisible by 2 and 5 or both?
There are 2000 such numbers.
How many 4 digit numbers can be made to give the sum of 6?
If repetition of digits is allowed, then 56 can.If repetition of digits is not allowed, then only 18 can.
How many 13 digit no are possible by using the digits 12345 which are divisible by 4 if repetition of digits is allowed?
5 ^12
How many 5 digit number can be formed using the digits 02345when repetition is allowed such that the number formed is divisible by 2 or 5 or both?
There are 2000 such numbers.
How many 3 digit number can be made using the digits 2 4 7 9?
24 three digit numbers if repetition of digits is not allowed. 4P3 = 24.If repetition of digits is allowed then we have:For 3 repetitions, 4 three digit numbers.For 2 repetitions, 36 three digit numbers.So we have a total of 64 three digit numbers if repetition of digits is allowed.
How many 2-digit numbers can be produce using the digits 123456789 if repetition is not allowed?
-123456787
Where d represents a digit from 0 9 how many different ISBN numbers are possible if repetition of digits is allowed?
There are 10 to the 10th power possibilities of ISBN numbers if d represents a digit from 0 to 9 and repetition of digits are allowed. That means there are 10,000,000,000 ISBN numbers possible.
How many 3 digits odd numbers can be formed from the digits 1 2 3 4 and 5 if repetition is not allowed?
125
How man 7 digit combinations can be made using numbers 0 through 9?
10^7 if the repetition of digits is allowed. 9*8*7*6*5*4*3 , if the repetition of digits is not allowed.
How many 3-digit numbers using the digits 0-7 are possible if repetition are allowed?
290
