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How many four digit numbers having all digits distinct can be formed which are not less than 4300?
Wiki User
∙ 12y ago
ans is 2856. But i dont know how to solve... Plz tell....
Wiki User
∙ 12y ago
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How many 6 digit numbers can be formed with 4 different digits?
The question can be re-stated as asking for the total number of permutations that can be derived from the following two groups of digits: AAABCD and AABBCD, where A, B, C and D are different. The number of ways of choosing the digit A, to be used three times, out of the ten digits {0, 1, 2, ... 9} is 10. Having done that, the number of ways of selecting 3 from the remaining 9 digits is 9C3 = (9*8*7)/(3*2*1) = 84. Thus there are 10*84 = 840 combinations of the form AAABCD. You now need all the distinct permutations of these 6 digits. The total number of permutations of 6 digits is 6! but because 3 of the digits are the same, these permutations are not all distinct. In fact, there are 6!/3! = 120 distinct permutations. That makes a total of 840*120 = 100800 such numbers. Next, the number of ways of choosing the digits A and B, each to be used twice, out of the ten digits {0, 1, 2, ... 9} is 10C2 = (10*9)/(2*1) = 45. Having done that, the number of ways of selecting C and D from the remaining 8 digits is 8C2 = (8*7)/(2*1) = 28. Thus there are 45*28 = 1260 combinations of the form AAABCD. You now need all the distinct permutations of these 6 digits. The total number of permutations of 6 digits is 6! but because 2 pairs of these digits are the same, these permutations are not all distinct. In fact, there are 6!/(2!*2!) = 180 distinct permutations. That makes a total of 1260*180 = 226800 such numbers. The grand total is, therefore, 100800 + 226800 = 327600 6-digit numbers made from 4 distinct digits.
How many two digits numbers having 1 as one digits are prime numbers?
They are: 11 13 17 19 31 41 61 and 71 which makes 8 of them
What are the functions of scientific notation?
To show very large or very small numbers, without writing out all the digits. To make it easy to compare such numbers, without having to count all the digits.
What does a way to write numbers using the digits 0-9 with each digit having a place value mean?
9
What is the number of 5 digit telephone numbers having atleast one of their digits repeated?
5 digit telephone numbers having at least one of their digits repeated is = total possible 5 digit telephone numbers - 5 digit telephone numbers without any digit being repeated. =(10*10*10*10*10)-(10*9*8*7*6) =100000-30240 =69760
Why you use commas when writing large numbers?
In representing large numbers, English texts use commas (or spaces) to separate each group of three digits. This is almost always done for numbers of six or more digits, and optionally for five (or even four) digits. This makes it easier to read the number without having to count how many place holders there are in the number as a whole.
What is the 7 digits number having different digits?
1234567
What is the greatest digits having 6 different digits?
987,654
How many possible three-digit passwords can be formed using digits 0 through 9 if no digits are repeated?
The first digit can be 0 through 9, ten possibilities. Having selected the first digit, you have 9 digits to pick from the second digit. Having selected the second digit, you have 8 digits to pick from the third digit. Hence total possibilities = 10 x 9 x 8 = 720
What is the smallest five digit number having three digit?
All five digit numbers have three digits. The smallest five digit whole number is 10,000
When numbering the pages of a book 624 digits were used find the number of pages in the book?
This problem can be solved by applying the counting principle to digits in consecutive page numbers. To begin, we need to separate numbers into their numbers of digits in order to multiply the page numbers to find the number of digits needed to express them. Assuming that your book begins on page 1, there are 9 page numbers having one digit only (counting principle: 9 - 1 + 1 = 9). Since each of these pages is numbered with one digit, the number of digits used is 9 so far. Continue with the pages each numbered with two digits. These are pages 10-99, comprising 90 pages (99 - 10 + 1 = 90). Every page number multiplied by 2 digits each is 180. With the 9 digits coming from single-digit pages, the number of digits used so far is now 189. We can continue in the same manner for pages expressed with three digits, 100-999, but having 435 (624 total - 189 so far = 435) digits left, we probably won't be able to get through all the three-digit numbers. Also, a book is likely to have under a thousand pages. To find out how many pages are left, we divide the number of digits left by the number of digits needed for each page: 435/3 = 145 pages left. Since 145 pages only account for the pages numbered with three digits each, we need to add pages numbered with one and two digits each in order to find the total number of pages. Before 145 pages began to be accounted for, we had accounted for the digits of 99 pages (each numbered using one or two digits each), so the total number of pages is 99 + 145 = 244.
Is -15 an integer?
No. Numbers having a dot in them aren't usually integers.
