9
Any number that has 4 or 5 digits. A digit in a number is one number place. 1 has 1 digit, 11 has 2 digits, 111 has 3 digits, and so on.
Numbers can be written using the digits 0-9 by assigning each digit a specific place value based on its position in the number. For example, in the number 345, the digit 3 represents 300 (3 in the hundreds place), 4 represents 40 (4 in the tens place), and 5 represents 5 (5 in the ones place). This positional notation allows us to express large values succinctly by combining digits according to their place values.
If the digits may not be repeated, there are 6x5x4x3x2x1 = 720 numbers, If digits can be repeated, the answer is 6x6x6x6x6x6 = 46,656 numbers If zero is ong the available digits but is excluded from the first place. 5x6x6x6x6x6=38,880 numbers
To form a two-digit number using the digits 0-9 without repetition, the first digit (the tens place) can be any digit from 1 to 9 (9 options), since a two-digit number cannot start with 0. The second digit (the units place) can then be any of the remaining 9 digits (including 0 but excluding the first digit). Therefore, the total number of two-digit numbers that can be formed is 9 (choices for the first digit) multiplied by 9 (choices for the second digit), resulting in 81 possible two-digit numbers.
To write the smallest 6-digit number with different digits and having 4 in the tens place, you should start with the smallest digits possible. The smallest non-zero digit is 1, so the number should start with 1. Following that, place 0 in the thousands place, then 2 in the hundreds place, and finally 3 in the units place. Therefore, the smallest 6-digit number is 102340.
No. A number with multiple digits does not have a place value. A single digit in a multi-digit number has a place value.
This is only possible if one of the digits is equal to zero. There are 90 3-digit numbers with a zero in the 10's place, and 90 3-digit numbers with a zero in the 1's place - and 9 numbers that have both a zero in the 10's place and a zero in the 1's place; these would be counted double if you just add the first two. So, you get: 90 + 90 - 9 such numbers.
Any number that has 4 or 5 digits. A digit in a number is one number place. 1 has 1 digit, 11 has 2 digits, 111 has 3 digits, and so on.
200
Numbers can be written using the digits 0-9 by assigning each digit a specific place value based on its position in the number. For example, in the number 345, the digit 3 represents 300 (3 in the hundreds place), 4 represents 40 (4 in the tens place), and 5 represents 5 (5 in the ones place). This positional notation allows us to express large values succinctly by combining digits according to their place values.
If the digits may not be repeated, there are 6x5x4x3x2x1 = 720 numbers, If digits can be repeated, the answer is 6x6x6x6x6x6 = 46,656 numbers If zero is ong the available digits but is excluded from the first place. 5x6x6x6x6x6=38,880 numbers
To form a two-digit number using the digits 0-9 without repetition, the first digit (the tens place) can be any digit from 1 to 9 (9 options), since a two-digit number cannot start with 0. The second digit (the units place) can then be any of the remaining 9 digits (including 0 but excluding the first digit). Therefore, the total number of two-digit numbers that can be formed is 9 (choices for the first digit) multiplied by 9 (choices for the second digit), resulting in 81 possible two-digit numbers.
To write the smallest 6-digit number with different digits and having 4 in the tens place, you should start with the smallest digits possible. The smallest non-zero digit is 1, so the number should start with 1. Following that, place 0 in the thousands place, then 2 in the hundreds place, and finally 3 in the units place. Therefore, the smallest 6-digit number is 102340.
They are written as numbers usually are. The place value of the digit immediately to the left of the decimal point is ones and the place value of all other digits is ten times the value of the digit to their right.
There are a total of 900 3-digt numbers (100 thru 999); Of these there are 9x9x8 = 648 numbers that do not contain repeating digits (first position: 9 possibilities, second place 9 possibilities; the 10 digits minus the one used in the first place. and third place 8 possibilities; 10 digits minus the two used in the first and second places) So, there should be 900-648=252 3-digit numbers with at least one repeating digit.
3,612,345,678
The two-digit numbers with both digits even are formed using the even digits 0, 2, 4, 6, and 8. However, since the first digit (the tens place) cannot be 0, the possible choices for the first digit are 2, 4, 6, and 8 (4 options). The second digit (the units place) can be 0, 2, 4, 6, or 8 (5 options). Therefore, the total number of two-digit numbers with both digits even is (4 \times 5 = 20).