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How many gallons each of 25 percent alcohol and 35 percent alcohol should be mixed to obtain 20 gallons of 32 percent alcohol?
Wiki User
∙ 11y ago
The question is best solved using basic algebra.
You need 20 gallons of 32% alcohol. This will contain 0.32*20 = 6.4 gallons of pure alcohol.
Now suppose you have X gallons of 25% alcohol in the mixture. That contains 0.25X gallons of pure alcohol.
Also, since you have 20 gallons in total, you must have 20-X gallons of the 35% alcohol. This will contain 0.35*(20-X) = 7 - 0.35X gallons of pure alcohol.
Then, the total amount of pure alcohol is 0.25X + 7 - 0.35X = 7 - 0.1X gallons.
So you have 7 - 0.1X = 6.4
or 0.6 = 0.1X or X = 6.
So the answer is 6 gallons of 25% alcohol and 14 gallons of the stronger stuff!
Wiki User
∙ 11y ago
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