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How many gallons of 50 percent antifreeze do you need to mix with 70 gallons of 15 percent antifreeze to get 40 percent?
Wiki User
∙ 12y ago
Suppose you add x gallons of 50%
Then total volume = x + 70
Of this, 40% or 0.40 is antifreeze so active volume = 0.40*(x + 70)
Also, considered separately, active volume = 0.50*x + 0.15*70
Thus 0.40x + 28 = 0.50x + 10.5
17.5 = 0.10 x so that x = 175 gallons.
Wiki User
∙ 12y ago
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How many gallons of a 50 percent antifreeze solution most be mixed with 90 gallons 10 percent antifreeze to get a mixture that is 40 percent antifreeze?
Multiply These Equals What you mix 50 .10+x 5+50x Plus what you have 90 .10 9 Equals what you need 40 x 40x 5+50x+9=40x 14+50x=40x 10x=14 x=1.4 140%
How many gallons of 80 percent antifreeze solution must be mixed with 100 gallons of 10 percent antifreeze to get a mixture that is 70 percent antifreeze?
600 gallons. To solve this think about the amount of antifreeze in the solution. When 10% antifreeze is added to x times as much 80% antifreeze, the resultant percentage antifreeze will be: (10 + 80x)/(1 + x) So to obtain a 70% solution, x will need to solve: (10 + 80x)/(1 + x) = 70 ⇒ 10 + 80x = 70 + 70x ⇒ 10x = 60 ⇒ x = 6 So to 100 gallons of 10% antifreeze solution, 100 x 6 = 600 gallons of 80% antifreeze solution will be needed to make it a 70% solution. Consider adding 100 gallons of 10% antifreeze and 100 gallons of 80% antifreeze together and then taking half the resultant solution, that is so that you have 100 gallons of the mixture; the amount of antifreeze in this 100 gallons is (10 gallons + 80 gallons) ÷ 2 = 45 gallons, that is a 45% mixture. Now consider adding 100 gallons of 10% antifreeze and 200 gallons of 80% antifreeze together and then taking a third of the resultant solution, that is so that you have 100 gallons of the mixture; the amount of antifreeze in this 100 gallons is (10 gallons + 2 x 80 gallons) ÷ 3 = 562/3 gallons, that is a 562/3% mixture. If x times as much of the 80% antifreeze is added to the If 1 gallon of 10% antifreeze was added together with 80% antifreeze, the resultant mixture will still be (10+90)/2 = 45%. So if x times as much of the 80% Consider the amount of antifreeze in the solution. When two solutions of the same volume is added, the amount of antifreeze in the same volume is half the new amount. Consider the ratio of anti-freeze to water in each of the solutions in fraction form of antifreeze/water: 10% is 10/90 70% is 70/30 80% is 80/20 When two ratios are added together, the amount of antifreeze in the solution is added together and the amount of water is added together to give some odd fraction maths: 10% + 80% = (10+80)/(90+20) = 90/110 =
How many gallons of gas does a BMW need to get to Florida from Texas?
About 30 Gallons
How many gallons do you need to fill up a 500 gallon propane tank to 60 percent?
60% * 500 = 300three hundred gallons (of liquid - the gas before being liquefied - takes up MUCH more volume)
How many gallons each of 25 percent alcohol and 35 percent alcohol should be mixed to obtain 20 gallons of 32 percent alcohol?
The question is best solved using basic algebra. You need 20 gallons of 32% alcohol. This will contain 0.32*20 = 6.4 gallons of pure alcohol. Now suppose you have X gallons of 25% alcohol in the mixture. That contains 0.25X gallons of pure alcohol. Also, since you have 20 gallons in total, you must have 20-X gallons of the 35% alcohol. This will contain 0.35*(20-X) = 7 - 0.35X gallons of pure alcohol. Then, the total amount of pure alcohol is 0.25X + 7 - 0.35X = 7 - 0.1X gallons. So you have 7 - 0.1X = 6.4 or 0.6 = 0.1X or X = 6. So the answer is 6 gallons of 25% alcohol and 14 gallons of the stronger stuff!
How many gallons of a 80 percent antifreeze solution must be mixed with 70 gallons of 20 percent antifreeze to get a mixture that is 70 percent antifreeze?
70 gallons of 20% solution contains 70*0.2 = 14 gallons of antifreeze. Suppose you need G gallons of the 80% antifreeze solution. This will contain 0.8*G gallons of antifreeze. Total volume of solution = G + 70 gallons Volume of antifreeze required in this solutions to make it a 70% solution is 0.7*(G + 70) = 0.7G + 49 gallons. Volume of antifreeze = 14 + 0.8G gallons So 0.7G + 49 = 14 + 0.8G 0.7G + 35 = 0.8G 35 = 0.1G 350 = G Answer: 350 gallons.
How many gallons of a solution that is 75 antifreeze must be mixed with 4 gallons of a 30 solution to obtain a mixture that is 50 antifreeze?
You will need 3.2 gallons.
How many gallons of a 50 percent antifreeze solution most be mixed with 90 gallons 10 percent antifreeze to get a mixture that is 40 percent antifreeze?
Multiply These Equals What you mix 50 .10+x 5+50x Plus what you have 90 .10 9 Equals what you need 40 x 40x 5+50x+9=40x 14+50x=40x 10x=14 x=1.4 140%
How much water should be added to 30 gallons of a solution that is 70 percent antifreeze in order to get a mixture that is 60 percent antifreeze?
First off do not use tap water. Use only distilled water. You will need to add 3 gallons of distilled water to the solution to get 60% antifreeze and 40% distilled water or a 60/40 mix.
How many gallons of 80 percent solution must be mixed with 100 gallons of a 15 percent antifreeze solution to get a mixture that is 70 percent antifreeze?
For these types of problems, I recommend finding the initial amount of antifreeze. To find this value, multiply the percentage of antifreeze (15%) by the amount of solution (100 gallons). This gets:0.15*100=15 gallons of antifreeze*Now we need make an equation that represents this problem. We let x be the number of gallons of 80% solution.(.80x+15)/(x+100)=0.70The top of the equation represents the amount of antifreeze, while the bottom is the total volume of the solution. If we divide these values, we should get the final concentration %, .70.Now we just need to manipulate the equation algebraically:.80x+15=.70x+70.10x=55x=550 gallons of 80% solution*If the concentration of a solution is given in percentage, it is probably referring to mass, not volume. Because of this, the values for the volume of antifreeze are actually untrue. But because the density of both substances remains the same, the final answer should be correct.
How many gallons of antifreeze does a 2001 peterbilt hold?
Need to know model and engine in order to answer this.
How many gallons of 80 percent antifreeze solution must be mixed with 100 gallons of 10 percent antifreeze to get a mixture that is 70 percent antifreeze?
600 gallons. To solve this think about the amount of antifreeze in the solution. When 10% antifreeze is added to x times as much 80% antifreeze, the resultant percentage antifreeze will be: (10 + 80x)/(1 + x) So to obtain a 70% solution, x will need to solve: (10 + 80x)/(1 + x) = 70 ⇒ 10 + 80x = 70 + 70x ⇒ 10x = 60 ⇒ x = 6 So to 100 gallons of 10% antifreeze solution, 100 x 6 = 600 gallons of 80% antifreeze solution will be needed to make it a 70% solution. Consider adding 100 gallons of 10% antifreeze and 100 gallons of 80% antifreeze together and then taking half the resultant solution, that is so that you have 100 gallons of the mixture; the amount of antifreeze in this 100 gallons is (10 gallons + 80 gallons) ÷ 2 = 45 gallons, that is a 45% mixture. Now consider adding 100 gallons of 10% antifreeze and 200 gallons of 80% antifreeze together and then taking a third of the resultant solution, that is so that you have 100 gallons of the mixture; the amount of antifreeze in this 100 gallons is (10 gallons + 2 x 80 gallons) ÷ 3 = 562/3 gallons, that is a 562/3% mixture. If x times as much of the 80% antifreeze is added to the If 1 gallon of 10% antifreeze was added together with 80% antifreeze, the resultant mixture will still be (10+90)/2 = 45%. So if x times as much of the 80% Consider the amount of antifreeze in the solution. When two solutions of the same volume is added, the amount of antifreeze in the same volume is half the new amount. Consider the ratio of anti-freeze to water in each of the solutions in fraction form of antifreeze/water: 10% is 10/90 70% is 70/30 80% is 80/20 When two ratios are added together, the amount of antifreeze in the solution is added together and the amount of water is added together to give some odd fraction maths: 10% + 80% = (10+80)/(90+20) = 90/110 =
How many gallons of antifreeze does a 2001 Lincoln town car hold or need?
According to the Owner Guide the cooling system capacity is 15.8 quarts It came from the factory with a 50 / 50 mix of antifreeze and distilled water So , 7.9 quarts or slightly under ( 2 gallons ) of antifreeze
How much antifreeze do you need?
How much coolant does your car or truck hold? You want to have one half pure antifreeze and one half water. If you want to mix your own and if your car holds 4 gallons of coolant then you need 2 gallons of distilled water and 2 gallons of antifreeze. Or you can buy the kind of antifreeze that is already mixed called "PRE-MIXED COOLANT" at most part stores and just fill it up.
How many gallons of antifreeze do you need for your 8 cylinder motor?
50% Antifreeze and 50% water mixed together. The winter months you need a higher ratio of antifreeze to water and in summer you need the 1/2 and 1/2 ration. It is not suggested to run pure Antifreeze in your car or truck. You can find pre mixed in the jugs at most Wal-marts/Kmarts/Auto Parts stores.
Is their a special kind of antifreeze for 1998 Lincoln navigator and how many gallons does it need?
According to the 1998 Lincoln Navigator Owner Guide : It came from the factory with a 50 / 50 mix of distilled water and GREEN color antifreeze ( meeting Ford specification ESE-M97B44-A ) The engine cooling system capacity is 20.8 U.S. quarts , so you would need : ( 10.4 quarts / 2.6 gallons of antifreeze ) for a 50 / 50 mix * Ford states not to exceed 60 % antifreeze
How many grams of active ingredient will you need to prepare 2.5 gallons of a 45.6 percent solution?
4314.9 grams
