That's going to depend on how deep the water is.
.015
To find out how much of the solution is needed to treat 30 gallons, you can set up a proportion. Since 1 gallon treats 2000 gallons, you can set up the proportion: 1 gallon is to 2000 gallons as x gallons is to 30 gallons. Solving for x gives you x = (1/2000) * 30 = 0.015 gallons. Thus, 0.015 gallons of the solution would be needed to treat 30 gallons.
I write 6 015 103 as 6 015 103.
since 1000 mm =1 m, then .015 mm = .015/1000 = .000015 m
.015
.015 kL
For water : .015 But you're trying to compare a volume (ml) with a weight {mass actually} (mg).
.015 mm = 15 µm
Since 015 = 15, 015 of 1% = 15 of 1% = 15% or 0.15
0.015
015% = 15% is equal to 0.15
Answer: 0.15 acre = 6,534 ft²