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Assuming that each person makes a shaking partnership just once and no one shakes there own hand,Consider the situation. The eight people are in a line. The first person goes down the line shaking hands with everyone else so he shakes hands 7 times. He then sits down.
The second person shakes hands with everyone left in line, six handshakes, and sits down, He has no need to shake ands with the sitting man as they already shook.
The remainder follow the same procedure, shaking hands with those standing, not shaking with those sitting.
The last man standing shakes with no one as no one is standing and sitsThe sum of hand shakings initiated by each person is 7+6+5+4+3+2+1+0 = 28
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How many people were at a party if There were 105 handshakes at a party and if each person at the party shook hands with exactly once with every other person.?
15 (15 * 15 - 15)/2 = 105
If every person at a party shakes the hand of every other person and there were 105 handshakes in all How many persons were present at the party?
The answer is 15 people. Each shook hands with 14 others, and there are half that many handshakes (pairs). The total number of pairs (distinct handshakes) within the group is defined by the formula T = [n!/(n-2)!] /2 Given T = 105 we get n!/(n-2)!=210 which implies n(n-1)=210 on solving we get n=15
10 people met at a party Each person shook every other hand once How many handshakes occurred?
9 + 8 + 7 + 6 + 5 + 4 + 3 + 2 + 1 = 55
How many people at a party if 28 hand shakes were done and everyone only did one handshake?
28 people each shook hands once...?
Which is correct--- they shook hands or they shaked hands?
"They shook hands" is correct.
How many handshakes would there be if 100 people shook hands?
200? D:
How many people were at a party if There were 105 handshakes at a party and if each person at the party shook hands with exactly once with every other person.?
15 (15 * 15 - 15)/2 = 105
How many handshakes would there be if four people shook hands with one another once?
6
Six people met and shook hands with one another How many Handshakes were there?
6*5/2 = 15
At a certain part 36 handshakes were exchanged everyone shook hands exactly once how many people attended the party?
Each handshake involves two people. If everyone shook only once then there were 36 x 2 ie 72 guests.
How many hand shakes would there be if 26 people shook hands?
there would be 26 handshakes if they were all done at once
How many handshakes within 50 people if each 1 shook hands with the other?
50*49/2 = 1225
At certain party there wereb 45 handshakes Everyone shook hands with everyone else exactly once how many people attended the party?
There were ten people at the party. This is a triangular sequence starting with two people: 1, 3, 6, 10, 15, 21, 28, 36, 45, etc. There's an equation for this. With n people at the party, the number of handshakes is n(n-1)/2.
If each of seven persons in a group shakes hands with each of the other six persons then a total of forty-two handshakes occurs?
The answer is 21 handshakes because the first person shakes hands with the other 6 people. The second person shakes hands with 5 people because they already shook hands with the first person. The third person shakes hands with 4 people because they already shook hands with the first and second person. The fourth person shakes hands with 3 people because they already shook hands with the first, second, and third. The fifth person shakes hands with 2 people because they already shook hands with the first, second, third, and fourth person. The sixth person shakes hands with the seventh person because the rest have already shaken hands with them. The seventh person doesn't have anyone else to shake hands with. Therefore the answer is 21 handshakes.
After a Student Council meeting all 14 members shook hands with every member How many handshakes were made?
91
If every person at a party shakes the hand of every other person and there were 105 handshakes in all How many persons were present at the party?
The answer is 15 people. Each shook hands with 14 others, and there are half that many handshakes (pairs). The total number of pairs (distinct handshakes) within the group is defined by the formula T = [n!/(n-2)!] /2 Given T = 105 we get n!/(n-2)!=210 which implies n(n-1)=210 on solving we get n=15
If each OF seven persons in a group shakes hands with each of the other six persons then a total of forty two handshakes occurs?
The correct answer is 21. The first person shakes hands with the other 6 people. The second person shakes hands with 5 people because they already shook hands with the first person. The third person shakes hands with 4 people because they already shook hands with the first and second person. The fourth person shakes hands with 3 people because they already shook hands with the first, second, and third. The fifth person shakes hands with 2 people because they already shook hands with the first, second, third, and fourth person. The sixth person shakes hands with the seventh person because the rest have already shaken hands with them. The seventh person doesn't have anyone else to shake hands with. So the total would be 21...
