The total number of handshakes that occur when each of seven persons shakes hands with each of the other six persons can be calculated using the combination formula. The formula for calculating the number of combinations of n items taken r at a time is nCr = n! / (r!(n-r)!). In this case, n = 7 and r = 2 (since each handshake involves 2 people), so the total number of handshakes is 7C2 = 7! / (2!(7-2)!) = 7! / (2!5!) = (7*6) / 2 = 21. Therefore, a total of 21 handshakes would occur in this scenario, not 42.
Everyone shakes hands with 4 other people. Since there are 5 people in the room this would suggest there are 5*4 = 20 handshakes. However, you would then be double counting handshakes: A shaking hands with B and B shaking hands with A is, in reality, only one handshake. Thus there are 5*4/2 = 10 handshakes in all.
If that happens you have to times ninexten and the answer would be 90 handshakes
i don't flipen knowww! thats why i want this to tell me!!
Nicholas Copernicus was afraid that no one would accept his theory so he did not release his book until the year of his death. Many say that he died with his book in his hands on his death bed.
there would be 26 handshakes if they were all done at once
You could never guarantee 1000 handshakes because the people may choose not to shake hands! If each person did shake hands with everyone else, then 46 people would suffice.
1000*999/2 = 499500
Everyone shakes hands with 4 other people. Since there are 5 people in the room this would suggest there are 5*4 = 20 handshakes. However, you would then be double counting handshakes: A shaking hands with B and B shaking hands with A is, in reality, only one handshake. Thus there are 5*4/2 = 10 handshakes in all.
14
Assuming players only shake hands with members of the other team and not their own team mates, there would be 11 players on one team, each of whom would shake the hands of 11 players on the other team. That makes 11*11 = 121 handshakes in all. If the players shook hands with everyone else, irrespective of which team they were on, there would be 22*21/2 = 231 handshakes.
28Good question. This is an 'analogue' of this puzzle: "Eight people meet for the first time. If they each shake hands with everyone else, how many handshakes are there?" There is a formula, but who would remember it?Imagine you and I are both among the eight people. You would shake hands with seven others. I would say the same thing, and so could each of the others.That gives 8x7 = 56, but you and I both counted the time we shook hands with one another , in fact each handshake is counted twice. The number of handshakes is actually 56/2 = 28.This can be generalized to say that the number of ways to choose 2 objects from a group of n objects is n(n-1)/2.
1/2 of (29 x 28) = 29 x 14 = 406
If that happens you have to times ninexten and the answer would be 90 handshakes
There would have been 45 handshakes among 10 people at a meeting. This can be calculated using the formula n(n-1)/2, where n represents the number of people.
Each person shakes hands with every other person at the end of the banquet. When person 1 shakes hands with person 2 that constitutes one handshake even though 2 people are involved. So the answer is 10 total handshakes because the 1st person will have 4 total handshakes(because he can't shake hands with himself, he has 4 and not 5 total handshakes), and then the 2nd person will have 3 total handshakes (you wouldn't say 4 handshakes because you've already included the handshake between person 1 & person 2 when calculating the first person's number of shakes) and so on for the remaining 3 people. On paper the math would look like this: 4+3+2+1=10 Alternatively: Each person shakes hands with 4 others so the answer looks like 5x4 = 20; However, in Fred shaking with 4 others, he shakes with Charlie, similarly, in Charlie shaking with 4 others he shakes with Fred. Thus the Fred-Charlie handshake has been counted twice (once by Fred, once by Charlie), as have all the handshakes, thus the answer is: 5x4 / 2 = 10.
66. Each of the 12 members shook hands with the 11 other people. That would make 12*11 hand shakes. BUT, the A shaking B's hand is the same event as B shaking A's hand so all these handshakes are double-counted. The actual number is half that ie 33. If you are more familiar with combinatorial mathematics, the answer is the number of combinations of two obejects from 12, which is 12C2 = 12*11/(2*1)