The total number of handshakes that occur when each of seven persons shakes hands with each of the other six persons can be calculated using the combination formula. The formula for calculating the number of combinations of n items taken r at a time is nCr = n! / (r!(n-r)!). In this case, n = 7 and r = 2 (since each handshake involves 2 people), so the total number of handshakes is 7C2 = 7! / (2!(7-2)!) = 7! / (2!5!) = (7*6) / 2 = 21. Therefore, a total of 21 handshakes would occur in this scenario, not 42.
Everyone shakes hands with 4 other people. Since there are 5 people in the room this would suggest there are 5*4 = 20 handshakes. However, you would then be double counting handshakes: A shaking hands with B and B shaking hands with A is, in reality, only one handshake. Thus there are 5*4/2 = 10 handshakes in all.
If that happens you have to times ninexten and the answer would be 90 handshakes
i don't flipen knowww! thats why i want this to tell me!!
Nicholas Copernicus was afraid that no one would accept his theory so he did not release his book until the year of his death. Many say that he died with his book in his hands on his death bed.
6
there would be 26 handshakes if they were all done at once
The total number of handshakes that occur when each of seven persons shakes hands with each of the other six persons can be calculated using the combination formula. The formula for calculating the number of combinations of n items taken r at a time is nCr = n! / (r!(n-r)!). In this case, n = 7 and r = 2 (since each handshake involves 2 people), so the total number of handshakes is 7C2 = 7! / (2!(7-2)!) = 7! / (2!5!) = (7*6) / 2 = 21. Therefore, a total of 21 handshakes would occur in this scenario, not 42.
You could never guarantee 1000 handshakes because the people may choose not to shake hands! If each person did shake hands with everyone else, then 46 people would suffice.
1000*999/2 = 499500
Everyone shakes hands with 4 other people. Since there are 5 people in the room this would suggest there are 5*4 = 20 handshakes. However, you would then be double counting handshakes: A shaking hands with B and B shaking hands with A is, in reality, only one handshake. Thus there are 5*4/2 = 10 handshakes in all.
14
Assuming players only shake hands with members of the other team and not their own team mates, there would be 11 players on one team, each of whom would shake the hands of 11 players on the other team. That makes 11*11 = 121 handshakes in all. If the players shook hands with everyone else, irrespective of which team they were on, there would be 22*21/2 = 231 handshakes.
28Good question. This is an 'analogue' of this puzzle: "Eight people meet for the first time. If they each shake hands with everyone else, how many handshakes are there?" There is a formula, but who would remember it?Imagine you and I are both among the eight people. You would shake hands with seven others. I would say the same thing, and so could each of the others.That gives 8x7 = 56, but you and I both counted the time we shook hands with one another , in fact each handshake is counted twice. The number of handshakes is actually 56/2 = 28.This can be generalized to say that the number of ways to choose 2 objects from a group of n objects is n(n-1)/2.
1/2 of (29 x 28) = 29 x 14 = 406
14 is incorrect Correct answer is 21* 7 persons in total, which means the first one will shake hands with 6 persons, the next in line will shake hands with 5 (given that he already shook hands with the first person). Calculation is: 6+5+4+3+2+1=21 *Applies to question if handshakes take place between new partners only, however in either case 14 can never be the answer.
100