The correct answer is 21. The first person shakes hands with the other 6 people. The second person shakes hands with 5 people because they already shook hands with the first person. The third person shakes hands with 4 people because they already shook hands with the first and second person. The fourth person shakes hands with 3 people because they already shook hands with the first, second, and third. The fifth person shakes hands with 2 people because they already shook hands with the first, second, third, and fourth person. The sixth person shakes hands with the seventh person because the rest have already shaken hands with them. The seventh person doesn't have anyone else to shake hands with. So the total would be 21...
Everyone shakes hands with 4 other people. Since there are 5 people in the room this would suggest there are 5*4 = 20 handshakes. However, you would then be double counting handshakes: A shaking hands with B and B shaking hands with A is, in reality, only one handshake. Thus there are 5*4/2 = 10 handshakes in all.
If that happens you have to times ninexten and the answer would be 90 handshakes
i don't flipen knowww! thats why i want this to tell me!!
you will have hands. really large hands, to be specific. and some apples too
6
there would be 26 handshakes if they were all done at once
You could never guarantee 1000 handshakes because the people may choose not to shake hands! If each person did shake hands with everyone else, then 46 people would suffice.
1000*999/2 = 499500
The correct answer is 21. The first person shakes hands with the other 6 people. The second person shakes hands with 5 people because they already shook hands with the first person. The third person shakes hands with 4 people because they already shook hands with the first and second person. The fourth person shakes hands with 3 people because they already shook hands with the first, second, and third. The fifth person shakes hands with 2 people because they already shook hands with the first, second, third, and fourth person. The sixth person shakes hands with the seventh person because the rest have already shaken hands with them. The seventh person doesn't have anyone else to shake hands with. So the total would be 21...
Everyone shakes hands with 4 other people. Since there are 5 people in the room this would suggest there are 5*4 = 20 handshakes. However, you would then be double counting handshakes: A shaking hands with B and B shaking hands with A is, in reality, only one handshake. Thus there are 5*4/2 = 10 handshakes in all.
14
Assuming players only shake hands with members of the other team and not their own team mates, there would be 11 players on one team, each of whom would shake the hands of 11 players on the other team. That makes 11*11 = 121 handshakes in all. If the players shook hands with everyone else, irrespective of which team they were on, there would be 22*21/2 = 231 handshakes.
28Good question. This is an 'analogue' of this puzzle: "Eight people meet for the first time. If they each shake hands with everyone else, how many handshakes are there?" There is a formula, but who would remember it?Imagine you and I are both among the eight people. You would shake hands with seven others. I would say the same thing, and so could each of the others.That gives 8x7 = 56, but you and I both counted the time we shook hands with one another , in fact each handshake is counted twice. The number of handshakes is actually 56/2 = 28.This can be generalized to say that the number of ways to choose 2 objects from a group of n objects is n(n-1)/2.
1/2 of (29 x 28) = 29 x 14 = 406
14 is incorrect Correct answer is 21* 7 persons in total, which means the first one will shake hands with 6 persons, the next in line will shake hands with 5 (given that he already shook hands with the first person). Calculation is: 6+5+4+3+2+1=21 *Applies to question if handshakes take place between new partners only, however in either case 14 can never be the answer.
100